Answer:
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²
Explanation:
Hi there!
The acceleration is defined as the change in velocity in a time:
a = Δv / Δt
Where:
a = acceleration.
Δv = change in velocity = final velocity - initial velocity.
Δt = elapsed time.
In this case:
Initial velocity = 60 mi/h
final velocity = 50 mi/h
elapsed time = 3.0 s
Let´s convert the time unit into h:
3.0 s · 1 h /3600 s = 1/1200 h
Now, let´s calculate the acceleration:
a = Δv / Δt
a = (50 mi/h - 60 mi/h) / 1/1200 h
a = -1.2 × 10⁴ mi/h²
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²
Answer:
Option B
Explanation:
According to quantum theory of radiation electromagnetic field or electromagnetic radiation( like light) produce by accelerated charge object and the quantum of EM radiations is photon which has discrete energy. So, EM field can have only certain values of total energy and no other value due the discrete nature of the energy of photon. Hence option B is correct
The rate at which a radioactive isotope<span> decays is measured in </span>half-life. The termhalf-life<span> is defined as the time it takes for one-</span>half<span> of the atoms of a radioactive material to disintegrate. </span>Half-lives<span> for various </span>radioisotopes<span> can range from a few microseconds to billions of years.</span>
Jeremy’s son has more mass, so it would take more forever to reach the same height as his daughter
Answer:
2.1 × 10⁻⁵ T
Explanation:
Given:
Inner radius, r = 4 mm = 0.004 m
Outer radius, R = 25 mm = 0.025 m
Current, I = 4 A
Distance of the point from the center, a = 17 mm = 0.017 m
μ₀ = 4π × 10⁻⁷ T·m/A
Now,
For the hollow cylinder magnetic field (B) is given as:
on substituting the respective values, we get
or
B = 2.1 × 10⁻⁵ T
