Answer: 29.50 m
Explanation: In order to calculate the higher accelation to stop a train without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:
f=μ*N the friction force is equal to coefficient of static friction multiply the normal force (m*g).
f=m.a=μ*N= m*a= μ*m*g= m*a
then
a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2
With this value we can determine the short distance to stop the train
as follows:
x= vo*t- (a/2)* t^2
Vf=0= vo-a*t then t=vo/a
Finally; x=vo*vo/a-a/2*(vo/a)^2=vo^2/2a= (49*1000/3600)^2/(2*3.14)=29.50 m
The gravitational potential energy of the rock is:
490 J at 50 m
196 J at 20 m
9.8 J at 1 m
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in the gravitational field.
For an object near the Earth's surface, the GPE is given by
where
m is the mass of the object
is the acceleration of gravity at Earth's surface
h is the heigth of the object relative to the ground
For the rock in this problem,
m = 1 kg
So its GPE at h = 50 m is
The GPE at h = 20 m is
While the GPE at h = 1 m is
Learn more about gravitational potential energy:
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#LearnwithBrainly
Answer:
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Explanation:
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Answer:
lol you literally answered a question with a link and you're telling people not to?
Mass = 40.14 - 33.79= 6.35 gram
vol = 13.3 ml
density = m/v = 6.35/13.3 = 0.477 g/ml