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frozen [14]
3 years ago
9

A circuit contains two light bulbs connected in parallel. What would happen to the brightness of each light bulb if two more lig

ht bulbs were added in parallel to the first ones?
A. The brightness of each bulb would decrease because the total resistance of the circuit would decrease.

B. The brightness of each bulb would increase because the total resistance of the circuit would increase.

C. The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.

D. The brightness of each bulb would remain the same even though the total resistance of the circuit would increase.
Physics
3 answers:
Alecsey [184]3 years ago
8 0
In order to say definitely what would happen, we need to make sure that
the light bulbs are the only items connected to the battery or power supply.
What I mean is:  You can't start out with, say, a string of Christmas tree
lights, and at some point in the string, there's an extra little bulb in parallel
with one of the lights in the string.  If that's the situation ... if there's anything else in the circuit besides the two light bulbs in parallel ... then we'd need
more information in order to predict what happens when we make changes
to that part of the circuit.

So the whole circuit consists of: 
Two light bulbs in parallel, connected to a battery.  That's all.

Now, we connect two MORE light bulbs in parallel with the first ones.
Now we have FOUR light bulbs, all in parallel, connected to the battery.

-- The battery would see the total resistance of the circuit DECREASE.
(An electron that leaves one terminal of the battery now has 4 ways to
reach the other side of the battery, instead of just two.  It's easier for
electrons to get there, so more of them make the trip every second.)

-- Did you hear that ?  "More electrons make the trip every second."
That means there's more current leaving the battery.

-- IF the battery or power supply is able to deliver the increased current,
then the original devices ... the original two light bulbs ... don't even know
that anything has happened.  Their brightness doesn't change.

-- Choice-C  says this.
_______________________________

I just told you that connecting more stuff in parallel makes no difference
to the devices that are already there.  If that sounds weird to you, then
let me tell you this:

EVERYTHING in your house is in parallel with everything else ! 
Every light, kitchen appliance, motor, heater, electric furnace, radio,
air conditioner, phone charger, TV, computer, mixer, microwave  ...
everything that plugs into a socket in the wall ... is in parallel with
everything else that you plug in.

When you plug in something new, or turn on something that was off,
it should have no effect on the things that were already running.
(If it does ... if, say,  the lights in kitchen go dim when you turn on
the microwave ... then the wiring in your house is a little bit skimpy
for running all the things that we run in our houses now.)

Marta_Voda [28]3 years ago
7 0

Answer;

C. The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.

Explanation;

-If light bulbs are connected in parallel to a voltage source, the brightness of the individual bulbs remains more-or-less constant as more and more bulbs are added to the circuit.

-The current increases as more bulbs are added to the circuit and the overall resistance decreases. In addition, if one bulb is removed from the circuit the other bulbs do not go out. Each bulb is independently linked to the voltage source

laila [671]3 years ago
6 0

Answer;

C. The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.

Explanation;

-If light bulbs are connected in parallel to a voltage source, the brightness of the individual bulbs remains more-or-less constant as more and more bulbs are added to the circuit.

-The current increases as more bulbs are added to the circuit and the overall resistance decreases. In addition, if one bulb is removed from the circuit the other bulbs do not go out. Each bulb is independently linked to the voltage source

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Define limitations in the operation conditions of a pn junction<br>​
suter [353]

Answer:

Such limitations are given below.

Explanation:

  • Each pn junction provides limited measurements of maximum forwarding current, highest possible inversion voltage as well as the maximum output level.
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6 0
4 years ago
14. Three identical light bulbs are connected in series, then are disconnected and arranged in parallel. For each of the scenari
Inessa [10]
In order to make things easier to describe and explain, let's call
the resistance of each bulb 'R', and the battery voltage 'V'.

a).  In series, the total resistance is 3R.
In parallel, the total resistance is R/3.
Changing from series to parallel, the total resistance of the circuit
decreases to 1/9 of its original value.

b).  In series, the total current is  V / (3R) .
In parallel, the total current is  3V / R .
Changing from series to parallel, the total current in the circuit
increases to 9 times its original value.

c).  In series, the power dissipated by the circuit is 

                                   (V) · V/3R  =  V² / 3R .

In parallel, the power dissipated by the circuit is

                                   (V) · 3V/R  =  3V² / R .

Changing from series to parallel, the power dissipated by
the circuit (also the power delivered by the battery) increases
to 9 times its original value.

8 0
3 years ago
Could we see a galaxy that is 20 billion light-years away?.
vichka [17]

Answer:

No

Explanation:

20 billion light-years away are beyond our sight and perspective on Earth and wouldn't be observable in our universe.

7 0
2 years ago
A voltmeter was used to check the coolant and a reading of 0.2 volt with the engine off was measured. A reading of 0.8 volt was
Julli [10]

Answer:

C. Technician B

Explanation:

Excessive Galvanic activity:

To check for excessive galvanic activity, voltmeter is used to check the coolant. If the voltmeter is giving a reading greater than 0.5 V, there is excessive galvanic activity. Excessive galvanic activity is solved by flushing the coolant fluid from engine and refiling it.

Electrolysis problem:

When the system is not properly ground, the cooling system accepts stray current and the coolant becomes an electrolyte which might eat up the radiator. To test for excessive electrolysis, start the engine and turn on all electrical accessories, if the reading is more than 0.5 V, there is electrolysis problem. Ground wires and connections should be checked at this point to stop stray current.

In our case, the first reading is 0.2 V(engine turned off) which is normal and there is no excessive galvanic activity. This means that Technician A is not correct. The second reading is 0.8 V when the engine and all electrical accessories are turned on. This reading is greater than 0.5 V which means there is an electrolysis problem. This means that Technician B is correct and ground wires and connections should be inspected and repaired.

7 0
3 years ago
1. 1500j of work was done to move a box 20m. What force was applied to the box ?
Fantom [35]

Answer:

1. 75N

2. 67,983 J (=67.98 kJ)

Explanation:

1. Work = Force x Distance

we are given that Work = 1,500J and Distance = 20m

hence,

Work = Force x Distance

1,500 = Force x 20

Force = 1,500 ÷ 20 = 75N

2. Potential Energy, PE = mass x gravity x change in height

we are given that mass = 165 kg and change in height = 42m

assuming that gravity, g = 9.81 m/s²

Potential Energy, PE = mass x gravity x change in height

Potential Energy, PE = 165 x 9.81 x 42 = 67,983 J (=67.98 kJ)

4 0
3 years ago
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