Answer:
As per Coulomb's law we know that force between two charges is given as
F = \frac{kq_1q_2}{r^2}F=
r
2
kq
1
q
2
here we know that
q_1 = 2.5 \times 10^{-6} Cq
1
=2.5×10
−6
C
q_2 = -5.0 \times 10^{-6} Cq
2
=−5.0×10
−6
C
r = 0.0050 mr=0.0050m
now from above formula we will have
F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=
(0.0050)
2
(9×10
9
)(2.5×10
−6
)(5×10
−6
)
F = 4500 NF=4500N
so they will attract towards each other as they are opposite in nature with force F = 4500 N
The mechanical energy of the car is 
Explanation:
The mechanical energy of an object is equal to the sum of its gravitational potential energy (GPE) and its kinetic energy (KE):
E = GPE + KE
The GPE of the car is given by:
where
m = 1000 kg is the mass of the car
is the acceleration of gravity
h = 30 m is the height of the car above the ground
Substituting,
The kinetic energy of the car is given by:
where
m = 1000 kg
v = 50 m/s is the speed of the car
Substituting,
Therefore, the mechanical energy is
Learn more about potential energy and kinetic energy:
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Answer:
19.98Joules
Explanation:
Energy possessed by the body is the kinetic energy
Kinetic Energy = 1/2mv²
m is the mass
v is the velocity
For the 4kg moving at 6m/s
kE = 1/2 * 4 * 6^2
KE = 1/2 * 4 * 36
KE = 72Joules
For the 4kg moving at 5.1m/s
kE = 1/2 * 4 * 5.1^2
KE = 1/2 * 4 *26.01
KE = 52.02Joules
Amount of Energy lost = 72 - 52.02
Amount of Energy lost = 19.98Joules
Hence the amount of Energy lost is 19.98Joules
Answer:
Explanation:
given data= 34.2 m/s
we have to convert it into km/s
as we know that
1 km=1000 m
so 1 m= 1/1000 =0.001 km
now we know that 1 min=60 sec
so 1 sec=1/60= 0.016 min
therefore
34.2m/s = 34.2*m/sec =34.2*0.001 km /0.016 min
so 34.2 m/s =2.1 km/min
