I = MR^2
The Attempt at a Solution:::
I total = (3M)(0)^2 + (2M)(L/2)^2 + (M)(L)^2
I total = 3ML^2/2
It says the answer is 3ML^2/4 though.
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mark it as brainliest.... ✌✌✌
A mechanical wave<span> requires an initial </span>energy<span> input. Once this initial </span>energy<span> is added, the </span>wave<span> travels through the medium until all its </span>energy is transferred<span>. In contrast, electromagnetic </span>waves<span> require no medium, but can still travel through one</span>
Answer:
Is your question asking for the muzzle velocity of the bullet?
Explanation:
I will assume it does
The bullet travels horizontally to the target in the same amount of time it falls 2.3 cm from vertical rest
s = ½at²
t = √(2s/g) = √(2(0.023) / 9.8) = 0.0685118...s
v = d/t = 47/0.0685118 = 686.01242...
v = 690 m/s
Answer:
10 m/s²
Explanation:
Acceleration: This the rate of change of velocity. The unit of acceleration is m/s²
From the question,
a = (v-u)/t.................... Equation 1
Where a = acceleration of the cheetah, v = final velocity of the cheetah, u = initial velocity of the cheetah, t = time.
Given: u = 0 m/s, v = 25 m/s, t = 2.5 s.
Substitute these values into equation 1
a = (25-0)/2.5
a = 25/2.5
a = 10 m/s²
Hence the acceleration of the cheetah = 10 m/s²
