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Virty [35]
3 years ago
5

14. Three identical light bulbs are connected in series, then are disconnected and arranged in parallel. For each of the scenari

os below indicate what changes (if any) take place (1 pt. ea.):
a. Total resistance of the circuit
b. Total current of the circuit
c. Power dissipated by the circuit
Physics
1 answer:
Inessa [10]3 years ago
8 0
In order to make things easier to describe and explain, let's call
the resistance of each bulb 'R', and the battery voltage 'V'.

a).  In series, the total resistance is 3R.
In parallel, the total resistance is R/3.
Changing from series to parallel, the total resistance of the circuit
decreases to 1/9 of its original value.

b).  In series, the total current is  V / (3R) .
In parallel, the total current is  3V / R .
Changing from series to parallel, the total current in the circuit
increases to 9 times its original value.

c).  In series, the power dissipated by the circuit is 

                                   (V) · V/3R  =  V² / 3R .

In parallel, the power dissipated by the circuit is

                                   (V) · 3V/R  =  3V² / R .

Changing from series to parallel, the power dissipated by
the circuit (also the power delivered by the battery) increases
to 9 times its original value.

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The rotational inertial of the hollow sphere, disk and ring are 2/3MR², 1/2MR² and MR² respectively.

Since the three objects are rolling from the same height, they have the same mechanical energy.

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7 0
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length of the train, L₁ = 90 m

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Total distance to be traveled, = L₁ + L₂

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Time of motion = 9.006 s ≅ 9.01 s

Therefore, the time taken for the train to cross the bridge is 9.01 s

5 0
3 years ago
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