The number of mole of lithium, Li needed for the reaction is 3.2 moles (Option D)
<h3>Balanced equation </h3>
4Li + N₂(g) → 2Li₂N
From the balanced equation above,
2 moles of Li₂N were obtained from 4 moles of Li
<h3>How to determine the mole of lithium needed </h3>
From the balanced equation above,
2 moles of Li₂N were obtained from 4 moles of Li
Therefore,
1.6 moles of Li₂N will be obtained from = (1.6 × 4) / 2 = 3.2 moles of Li
Thus, 3.2 moles of Li are needed for the reaction
Learn more about stoichiometry:
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Since water does not have charged particles, water is a non-conductor. When some solutes dissolve in water they allow an electric current to flow through the water and the solution conducts electricity. These solutes are called electrolytes. ... Non-electrolytes like sugar dissolve to form molecules in solution.
Answer: you cannot change the subscripts in a formula in order to balance a chemical equation because the subscripts indicate the number of each kind of atom in the formula,
Each compound has an invaraible chemical formula which tells how many atoms of every kind constitute the compound.
Varyng the subscripts is a modification of the chemical formula, meaning that you end up with a different compound.
On the other hand, by varying the coefficients, you only modifiy the number of unit formulas (number of molecules of the compound) that intervene in the reaction, which is what you want to indicate by balanceing reactants and products.
Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and respectively.
Explanation :
Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).
As we are given that:
Fuel value =
Molar mass of pentane = 72 g/mol
Fuel value =
Fuel value = 49.09 kJ/g
Now we have to calculate the fuel density of pentane.
Fuel density = Fuel value × Density
Fuel density = (49.09 kJ/g) × (0.626g/mL)
Fuel density = 30.73 kJ/mL =
Thus, the fuel density of pentane is
Q1)
When the diver descends 34 feet;
total pressure on the diver - air pressure+ pressure from 34 feet of water
air pressure - 1 atm
water pressure - 1 atm
therefore total pressure at 34 feet deep - 2 atm
Since water pressure increases with depth, according to the following equation;
P = hpg
h - height of water column above the point of pressure
p - density of water
g - gravitational acceleration
P - pressure
as p and g are constant P is proportional to height, therefore when the height increases, pressure too increases proportionally
new height is 102 feet
that's 34*3 = 102 feet
so for every 34 feet, pressure increases by 1 atm
therefore at 102 feet - 1 atm times 3 = 3 atm
therefore total pressure at the new point = 1 atm (air pressure) + 3 atm (water pressure)
total pressure = 4 atm
Q2)the reason why a person on land is not affected by the pressure exerted on him by the atmosphere around him is as the persons body too exerts an almost equal amount of pressure from inside. Therefore the pressure acting on him and pressure exerted by him is equalised so he wont feel the effect of atmospheric pressure.
Similarly when the person dives into water since the body also contains water inside, the pressure exerted on him by water is equal to the internal pressure coming from him. Therefore he won't feel a huge effect by the water pressure.
However the air spaces inside the person will have the pressure it had at the surface of water, but when the person has dived inside the water pressure is much higher therefore there's a pressure difference between that of the water pressure and pressure inside the air spaces. This may cause a squeeze where the air spaces tend to compress. To avoid this condition, the air spaces should be equalised.