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Naily [24]
4 years ago
8

Pentane is a small liquid hydrocarbon, between propane and gasoline in size at C5H12. The density of pentane is 0.626 g/mL and i

ts enthalpy of combustion is ΔH°comb = –3535 kJ/mol. Estimate the fuel value and the fuel density of pentane.
Chemistry
1 answer:
Goshia [24]4 years ago
4 0

Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and 3.073\times 10^4kJ/L respectively.

Explanation :

Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).

As we are given that:

\Delta H^o_{comb}=-3535kJ/mol

Fuel value = \frac{\Delta H^o_{comb}}{\text{Molar mass of pentane}}

Molar mass of pentane = 72 g/mol

Fuel value = \frac{3535kJ/mol}{72g/mol}

Fuel value = 49.09 kJ/g

Now we have to calculate the fuel density of pentane.

Fuel density = Fuel value × Density

Fuel density = (49.09 kJ/g) × (0.626g/mL)

Fuel density = 30.73 kJ/mL = 3.073\times 10^4kJ/L

Thus, the fuel density of pentane is 3.073\times 10^4kJ/L

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Answer:

Sojourner is the Mars Pathfinder robotic Mars rover that landed on July 4, 1997 in the Ares Vallis region, and explored Mars for around three months. It has front and rear cameras and hardware to conduct several scientific experiments.

Explanation:

8 0
3 years ago
A mixture of methane and carbon dioxide gases contains methane at a partial pressure of 431 mm Hg and carbon dioxide at a
KatRina [158]

Answer:

XCH₄ = 0.461

XCO₂ = 0.539

Explanation:

Step 1: Given data

  • Partial pressure of methane (pCH₄): 431 mmHg
  • Partial pressure of carbon dioxide (pCO₂): 504 mmHg

Step 2: Calculate the total pressure in the container

We will sum both partial pressures.

P = pCH₄ + pCO₂

P = 431 mmHg + 504 mmHg = 935 mmHg

Step 3: Calculate the mole fraction of each gas

We will use the following expression.

Xi = pi / P

XCH₄ = pCH₄/P = 431 mmHg/935 mmHg = 0.461

XCO₂ = pCO₂/P = 504 mmHg/935 mmHg = 0.539

3 0
3 years ago
A sample of pure lithium carbonate contains 18.8% lithium by mass. What is the % lithium by mass in a sample of pure lithium car
VashaNatasha [74]

Answer:

There is 18.8% lithium by mass in second sample

Explanation:

Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-

Let's assume weight of first sample is x g

So, 100 g of sample contains 18.8 g of lithium

Hence, x g of sample contains (\frac{18.8}{100}\times x) g of lithium

Now, the second sample has weight equal to 2x g

So, 2x g of sample contains (\frac{18.8}{100}\times 2x) g of lithium

So, % lithium by mass in second sample = (\frac{\frac{18.8}{100}\times 2x}{2x})\times 100 % = 18.8%

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4 years ago
How many moles of each element are in 1 mole of ammonium nitrate?
liubo4ka [24]

Answer:

<h2><u>Of moles of NH4NO3 = 16/80 i.e. 0.2 moles of Ammonium Nitrate. 1 molecule of NH4NO3 contains 1 atom of N. Hence, 1 mole of NH4NO3 would contain 1 mole of Nitrogen atoms and therefore 0.2 moles of NH4NO3 should contain 0.2 moles of Nitrogen atoms</u>.</h2>

Explanation:

3 0
4 years ago
Convert 145 meters to kilometers.
Sphinxa [80]

Divide by 1000

145÷1000=0.145

Hope this will be helpful.

4 0
1 year ago
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