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4 years ago

Help! I can't find this answer anywhere!

Chemistry

1 answer:

Gnom [1K]4 years ago

8 0

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A car is traveling at 88 ft/sec. What is the car's speed in miles/hour?

sergejj [24]

Something travelling at one foot per second is traveling about 0.682 miles per hour, so it should be roughly 60mph

6 0

3 years ago

How many moles of Kr are contained in 398 mg of Kr?

bagirrra123 [75]

The mass of 1 mole of an element is its atomic weight on the Periodic Table in grams.

1g = 1000mg

The mass of 1 mole of Kr = 83.80g Kr

Convert mg Kr to g Kr.

398mg Kr x (1g/1000mg) = 0.398g Kr

Convert g Kr to mol Kr.

0.398g Kr x (1mol Kr/83.80g Kr) = 4.75x10-3mol Kr

8 0

3 years ago

~ WILL MARK AS BRAINLIEST ~

Genrish500 [490]

Answer:

200 grams is the mass of 15% of the solution of lime that is formed by dissolving 30g of calcium hydroxide in water.

Explanation:

Mass of solution = M

Mass percentage of the solution of lime = 15%

Mass of lime or calcium hydroxide = m = 30 g

The Formula of mass percentage is given as :

$m/m\%=\frac{m}{M}\times 100$

On substituting the values in ab above formula :

$15\%=\frac{30 g}{M}\times 100$

$M=\frac{30 g}{15}\times 100=200 g$

200 grams is the mass of 15% of the solution of lime that is formed by dissolving 30g of calcium hydroxide in water.

7 0

3 years ago

Determine the partial negative charge on the bromine atom in a c−br bond. the bond length is 1.93 å and the bond dipole moment i

vaieri [72.5K]

Answer:

The value is $x = 0.151 \ e$

Explanation:

From the question we are told that

The bond length is $l = 1.93\ \r a = 1.93 *1 *10^{-10} =1.93 *10^{-10}\ m$

The bond dipole moment is $\mu = 1.40 d = 1.40 * 3.33564 *10^{-30} = 4.6699 *10^{-30} \ C \cdot m$

Generally the dipole moment is mathematically represented as

$\mu = Q * l$

Here Q is the partial negative charge on the bromine atom

$Q = \frac{\mu}{ l}$

=> $Q = \frac{4.6699 *10^{-30}}{ 1.93 *10^{-10} }$

=> $Q = 2.42 *10^{-20} C$

Generally

1 electronic charge(e) is equivalent to $1.60*10^{-19} C$

So x electronic charge(e) is equivalent to $Q = 2.42 *10^{-20} C$

=> $x = \frac{2.42 *10^{-20}}{1.60*10^{-19} }$

=> $x = 0.151 \ e$

3 0

3 years ago

Cuanto se demora un clavo en un envase con vinagre en oxidarse?

Alexxandr [17]

Answer:

Verter lentamente partes iguales de vinagre y peróxido de hidrógeno para formar la solución. Mezclar estos dos ingredientes crea una pequeña cantidad de ácido peracético que oxidará el metal en la uña y creará óxido. La solución debe empezar a inflamarse y ponerse roja en los próximos cinco minutos.

Explanation:

6 0

3 years ago