Question

Automobile antifreeze is a mixture that consists mostly of water and ethylene glycol (C2H4(OH)2). What is the volume percent the ethylene glycol in the antifreeze mixture if it is created by mixing 3.00 gal of ethylene glycol with 2.00 gal water?

Answer 1

Answer:

60.00% is the volume percent the ethylene glycol in the antifreeze mixture.

Explanation:

Volume of the ethylene glycol in the mixture = 3.00 gal

Volume of the water in the mixture = 2.00 gal

Total volume of the mixture =3.00 gal + 2.00 gal = 5.00 gal

Volume percent the ethylene glycol :

$\frac{\text{Volume of solute}}{\text{Volume of solution or mixture}}\times 100$

$\%=\frac{3.00 gal}{5.00 gal}\times 100=60.00\%$

60.00% is the volume percent the ethylene glycol in the antifreeze mixture.