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3 years ago

How is an image produced by a plane mirror different than an image produced by a convex mirror

2 answers:

6 0

The light that is reflected always from you conCAVE or conVEX meaning the light that hits the mirror reflects away from you while a reflection of a plane mirror is directly reflected image without deviation

puteri [66]3 years ago

6 0

Answer:

When light impacts a plane mirror, the light ray is reflected with the same angle as the incident light ray.

For the curved mirrors, like the convex mirror, the normal surface of the mirror is not plane, so the angles change, for example, a light ray that includes horizontally in a curved part (not in the middle, a little bit above it for example) will impact a curved surface, and the reflected light ray will have a direction that "goes away" from the center of the mirror.

This means that those mirrors produce an image like a plane mirror right in the middle, and as you go to the sides, the image starts to be dilated.

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In an RLC series circuit that includes a source of alternating current operating at fixed frequency and voltage, the resistance

maw [93]

Answer:

Capacitive Reactance is 4 times of resistance

Solution:

As per the question:

R = $X_{L} = j\omega L = 2\pi fL$

where

R = resistance

$X_{L} = Inductive Reactance$

f = fixed frequency

Now,

For a parallel plate capacitor, capacitance, C:

$C = \frac{\epsilon_{o}A}{x}$

where

x = separation between the parallel plates

Thus

C ∝ $\frac{1}{x}$

Now, if the distance reduces to one-third:

Capacitance becomes 3 times of the initial capacitace, i.e., x' = 3x, then C' = 3C and hence Current, I becomes 3I.

Also,

$Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}$

Also,

Z ∝ I

Therefore,

$\frac{Z}{I} = \frac{Z'}{I'}$

$\frac{\sqrt{R^{2} + (R - X_{C})^{2}}}{3I} = \frac{\sqrt{R^{2} + (R - \frac{X_{C}}{3})^{2}}}{I}$

${R^{2} + (R - X_{C})^{2}} = 9({R^{2} + (R - \frac{X_{C}}{3})^{2}})$

${R^{2} + R^{2} + X_{C}^{2} - 2RX_{C} = 9({R^{2} + R^{2} + \frac{X_{C}^{2}}{9} - 2RX_{C})$

Solving the above eqn:

$X_{C} = 4R$

6 0

2 years ago

The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in

vivado [14]

The force the escaping gas exerts of the rocket is 10.42 N.

<h3>Force escaping gas exerts</h3>

The force the escaping gas exerts of the rocket is calculated as follows;

F = m(v - u)/t

where;

m is mass of the rocket
v is the final velocity of the rocket
u is the initial velocity of the rocket
t is time of motion

F = (0.25)(40 - 15)/0.6

F = 10.42 N

Thus, the force the escaping gas exerts of the rocket is 10.42 N.

Learn more about force here: brainly.com/question/12970081

#SPJ1

7 0

1 year ago

Three 7 0hm resistors are connected in series across a 10 V battery. What is the equivalent resistance of the circuit?

Tomtit [17]

Given

Three 7 ohm resistor are in series.

The battery is V=10V

To find

The equivalent resistance

Explanation

When the resistance are in series then the resistance are added to find its equivalent.

Thus the equivalent resistance is:

$R=7+7+7=21\Omega$

Conclusion

The equivalent resistance is 21 ohm

4 0

5 months ago

Which term describes an image that is in the opposite orientation than the object from which it was formed? virtual erect invert

DiKsa [7]

Answer:

lateral

...............

7 0

2 years ago

Why does a third class lever cannot magnify force?

maw [93]

Explanation:

The third class lever cannot magnify our force because in third class lever the effort it between the load and the fulcrum. Also, in this type of lever no matter where the force is applied, it is always greater than the force of load. Hence, That type of lever cannot magnify our force.

5 0

2 years ago