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4 years ago

How is an image produced by a plane mirror different than an image produced by a convex mirror

2 answers:

6 0

The light that is reflected always from you conCAVE or conVEX meaning the light that hits the mirror reflects away from you while a reflection of a plane mirror is directly reflected image without deviation

puteri [66]4 years ago

6 0

Answer:

When light impacts a plane mirror, the light ray is reflected with the same angle as the incident light ray.

For the curved mirrors, like the convex mirror, the normal surface of the mirror is not plane, so the angles change, for example, a light ray that includes horizontally in a curved part (not in the middle, a little bit above it for example) will impact a curved surface, and the reflected light ray will have a direction that "goes away" from the center of the mirror.

This means that those mirrors produce an image like a plane mirror right in the middle, and as you go to the sides, the image starts to be dilated.

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You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between

Tatiana [17]

Explanation:

Given that,

Mass of ball, m = 0.425 kg

Initial speed of the ball, u = 12 m/s

Initial speed of a person, u' = 0

Mass of a person, m' = 68 kg

(a) Let V is the combined speed of the person and the ball. Using conservation of momentum as :

$mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{0.425\times 12+0}{(0.425+68)}\\\\V=0.0745\ m/s$

(b) If the ball hits the person and bounces off his chest, so afterwards it is moving horizontally at 9.00 m/s in the opposite direction,. Let v' is the speed of the person after the collision. So,

$mu+m'u'=mv+m'v'$

v = -9 m/s

$mu=mv+m'v'\\\\v'=\dfrac{m(u-v)}{m'}\\\\v'=\dfrac{0.427\times (12-(-9))}{68}\\\\v'=0.131\ m/s$

Hence, this is the required solution.

4 0

3 years ago

One kg of air contained in a piston-cylinder assembly undergoes a process from an initial state whereT1=300K,v1=0.8m3/kg, to a f

lutik1710 [3]

Answer:

1. Yes, it can occur adiabatically.

2. The work required is: 86.4kJ

Explanation:

1. The internal energy of a gas is just function of its temperature, and the temperature changes between the states, so, the internal energy must change, but how could it be possible without heat transfer? This process may occur adiabatically due to the energy balance:

$U_{2}-U_{1}=W$

This balance tell us that the internal energy changes may occur due to work that, in this case, si done over the system.

2. An internal energy change of a gas may be calculated as:

$du=C_{v}dT$

Assuming $C_{v}$ constant,

$U_{2}-U_{1}=W=m*C_{v}(T_{2}-T_{1})$

$W=0.72*1*(420-300)=86.4kJ$

8 0

4 years ago

A meter stick whose mass is 330 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a

Sophie [7]

Answer:

initial magnitude will be 9 N and direction will be to the right

Explanation:

force= 9N

mass m= 330 grams

acceleartion = a

from newtons 2nd law of motion we write

$F= \frac{\mathrm{dP} }{\mathrm{d} t}$

dP is the chage in momentum dt is time taken and F is the Force applied

$9N= \frac{\mathrm{dP} }{\mathrm{d} t}$

this shows that the rate of change of momentum is 9 N

we also know that F= ma

putting values we get

$9= 0.330\times a$

a= 27.27 m/sec^2

The direction of acceleration will along the direction of force applied. So will be the direction of change momentum as in F=ma, mass is the scalar quantity and direction of force dictates the direction of motion. Hence, initial magnitude will be 9N and direction will be to the right

3 0

3 years ago

I'll give you a BRAINLIEST if you help me with these questions and they have to be correct.

irina1246 [14]

2. 3 I think I’m not sure

7 0

3 years ago

Rudy plans to conduct an experiment using three rosebushes of the same variety and size. His hypothesis is that the plant

Gala2k [10]

Answer: B) He has too many independent variables.

Explanation: Nothing in the experiment is a constant or being measured.

5 0

3 years ago