Answer:
Sample Response: To write a two-variable equation, I would first need to know how much Maya’s allowance was. Then, I would need the cost of playing the arcade game and of riding the Ferris wheel. I could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. My variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation I could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.
Answer:
85,910
You get this because whenever there are three digits after a number you add a comma as seen in the number there are three digits after 85 so you add a comma.
Hope it helps bai!
A. c + 7 ≤ 3
c ≤ -4
a = 2
b. c - 3 > 1
c > 4
b = 3
c. c - 7 < 3
c < 10
c = 2
Answer:
Yes
Step-by-step explanation:
Because since it tells you that x>7 and also it tells you if 7.1 is a solution. So what you need to do is plug in 7.1 instead of x and see if it's true or not. So is 7.1 greater than 7. Well yes it is and that makes it a solution. Hope this helps. Ask me any question if you need help with anything else. :)
Answer:
The factors of x^3+2x^2+5x+10 are (x^2+5)(x+2)
Step-by-step explanation:
x^3+2x^2+5x+10
Group the expression by two:
=(x^3+2x^2)+(5x+10)
Factor out GCF in each group.
=x^2(x+2)+5(x+2)
Note:(The binomials in parentheses should be the same, if not the same... there is an error in the factoring or the expression can not be factored.)
Now factoring out the GCF which basically has you rewrite what is in parentheses and place other terms left together:
=(x^2+5)(x+2)
Thus the factors of x^3+2x^2+5x+10 are (x^2+5)(x+2)....
