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Veseljchak [2.6K]
3 years ago
9

What is the name of this hydrocarbon? hexane heptane octane pentane

Chemistry
2 answers:
jenyasd209 [6]3 years ago
8 0

Answer : The name of the given hydrocarbon is, pentane.

Explanation :

The basic rules for naming of organic compounds are :

  • First select the longest possible carbon chain.
  • For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
  • A suffix '-ane' is added at the end of the name of alkane.
  • If two of more similar alkyl groups are present, then the words 'di', 'tri' 'tetra' and so on are used to specify the number of times these alkyl groups appear in the chain.

In the given hydrocarbon, the longest possible carbon chain number is 5 that means we add prefix 'pent' and suffix '-ane'. So, the name of given hydrocarbon will be, pentane.

Hence, the correct option is, pentane.

pav-90 [236]3 years ago
5 0

I believe it is pentane..Try that!


Hope it helps, sorry if it doesn't but that's the answer I just choose for my unit test on edgnty.

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INFORMATION:

We have the following statements

And we must complete them

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To complete the statements, we need to classify matter according to its state:

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Concentrated hydrogen peroxide solutions are explosively decomposed by traces of transition metal ions (such as Mn or Fe): 2H2O2
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Answer:

23.0733 L

Explanation:

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus, moles are:

moles= \frac{62.5\ g}{34\ g/mol}

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2H_2O_2_{(aq)}\rightarrow2H_2O_{(l)}+O_2_{(g)}

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Also,

1 mole of hydrogen peroxide decomposes to give 1/2 mole of oxygen gas.

So,

1.8382 moles of hydrogen peroxide decomposes to give \frac {1}{2}\times 1.8382 mole of oxygen gas. Moles of oxygen gas produced = 0.9191 molGiven: Pressure = 746 torr
The conversion of P(torr) to P(atm) is shown below:
[tex]P(torr)=\frac {1}{760}\times P(atm)

So,

Pressure = 746 / 760 atm = 0.9816 atm

Temperature = 27 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (27 + 273.15) K = 300.15 K

Using ideal gas equation as:

PV=nRT

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P is the pressure

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n is the number of moles

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R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9816 atm × V = 0.9191 mol × 0.0821 L.atm/K.mol × 300.15 K

<u>⇒V = 23.0733 L</u>

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