Answer:
mass O2 = 222.5 g
Explanation:
- %wt = ((mass compound)/(mass sln))×100
balance reaction:
∴ %wt H2 = 11 % = ((mass H2)/(mass H2O))×100
∴ %wt O2 = 89 % = ((mass O2)/(mass H2O))×100
∴ mass H2O 250 g
⇒ mass O2 = (0.89)(250 g)
⇒ mass O2 = 222.5 g
Calculate the number of moles for each element. n=m/M Then compare, and which ever one is lowest is the limiting reactant because no more products can form without one or the other.
Answer:
b i think but I'm not 100%
I’m pretty sure it’s abode and cathode
