In a heterogeneous mixture the substances are not evenly distributed (chocolate chip cookies, pizza, rocks) Page 2 Within the categories of homogeneous and heterogeneous mixtures there are more specific types of mixtures including solutions, alloys, suspensions, and colloids.
Answer:
Second step
(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)
Explanation:
This reaction involves;
First the ionization of the tertiary halide to firm a carbocation
Secondly the attack of the hydroxide ion on the carbocation to form tert-butanol
First step;
(CH3)3CBr (aq) → (CH3)3C+ (aq) + Br- (aq)
Second step
(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)
This second step completes the reaction mechanism.
A dipeptide is formed when 2 amino acids are joined together by a peptide linkage.
Each amino acid molecule contains an amino group ( -NH₂) and a carboxyl ( -COOH) group. During peptide formation, a carboxyl group of one amino acid reacts with amino group of the other , resulting in the formation of a linkage known as "peptide linkage". A water molecule is also eliminated in this reaction.
A general peptide formation reaction can be written as

In the above reaction, we can see a peptide linkage ( -CONH-) getting formed between 2 amino acid molecules.
In the given molecule the peptide linkage is shown by drawing a box around it. Please refer to the attached image.
If we want to know the amino acid molecules from which this peptide is formed, we will simply break the CO-NH bond.
We will add -OH group to CO part and -H to NH part to get 2 amino acid molecules as shown in the picture.
The two amino acids thus formed are Serine & Cysteine.
Serine is designated as "Ser" and Cysteine is designated as "Cys"
Therefore the given dipeptide is designated as "Ser-Cys"
Answer:
hco I believe
Explanation:
Pretty sure about this, when do you need to put it in?
I think the answer is chemical change