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Goshia [24]
3 years ago
5

What is the mass % of acetonitrile in a 2.17 M solution of acetonitrile (MM = 41.05 g/mol) in water? The density of the solution

is 0.810 g/mL.
Chemistry
1 answer:
jonny [76]3 years ago
5 0

why how what what what

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Boron has primarily two isotopes, one with an atomic mass of 11.0 amu and another with an atomic mass of 10.0 amu. If the abunda
Masja [62]

Answer:

The atomic mass of the boron atom would be <em>10.135</em>

Explanation:

This is generally known as relative atomic mass.

Relative atomic mass or atomic weight is a physical quantity defined as the ratio of the average mass of atoms of a chemical element in a given sample to the atomic mass of 1/12 of the mass of a carbon-12 atom. Since both quantities in the ratio are masses, the resulting value is dimensionless; hence the value is said to be relative and does not have a unit.

<em>Note that the relative atomic mass of atoms is not always a whole number because of it being isotopic in nature.</em>

  • <em>Divide each abundance by 100 then multiply by atomic mass</em>
  • <em>Do that for each isotope, then add the two result. Thus</em>

Relative atomic mass of Boron = (18.5/100 x 11) + (81/100 x 10)

                                                 = 2.035 + 8.1

                                                 = 10.135

5 0
3 years ago
How many molecules are contained in 0.800 mol o2?
Ksenya-84 [330]
Multiply .800 moles of O2 by Avagadro's number divided by 1 mole. This will get rid of the moles on the bottom and leave you with molecules. So technically .800 times 6.02x10^23.
6 0
3 years ago
Any help with atomic radius, ionization &amp; electronegativity? See picture please! I dont really understand any of the three.​
enyata [817]
18)
a. Ra
d. Ag
19)
a. C
b. Br
c. Mg
20)
a. S
b. Br
c. O

Sorry wasn’t sure about some of them in #18
Hope the notes are helpful.

8 0
3 years ago
Calculate the potential energy of a 25kg ball sitting 25m high
Mariulka [41]
The answer is 6,125. To get this you multiply both by 9.8
8 0
3 years ago
Q #13 How many moles of MgCl2 are there in 350. g of compound?
Vaselesa [24]

<u>Answer:</u>

3.67 moles

<u>Step-by-step explanation:</u>

We need to find out the number of MgCl_2 moles present in 350 grams of a compound.

Molar mass of Mg = 24.305

Molar mass of Cl_2 = 35.453

So, one mole of MgCl_2 = 24.305 + (35.453 * 2) = 95.211g

1 Mole in 1 molecule of MgCl_2 = \frac{1}{95.211} = 0.0105

Therefore, number of moles in 350 grams of compound = 0.0105 * 350

= 3.67 moles



8 0
3 years ago
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