Answer:
Is this an actual question that you had for school?
Explanation:
Answer:
None of the options are correct. The correct answer is 30020J
Explanation:
Data obtained from the question include:
Mass (M) = 2000g
Initial temperature (T1) = 10°C
Final temperature (T2) = 29°C
Change in temperature (ΔT) = T2 - T1 = 29°C - 10°C = 19°C
Heat (Q) =?
Specific heat capacity (C) of granite = 0.79J/g°C
Applying the equation Q = MCΔT, the heat absorbed by the granite rock can be obtained as follow:
Q = MCΔT
Q = 2000 x 0.79 x 19
Q = 30020J
Answer:
2.40 M
Explanation:
The molarity of a solution tells you how many moles of solute you get per liter of solution.
Notice that the problem provides you with the volume of the solution expressed in milliliters,
mL
. Right from the start, you should remember that you must convert this volume to liters by using the conversion factor
1 L
=
10
3
mL
Now, in order to get the number of moles of solute, you must use its molar mass. Now, molar masses are listed in grams per mol,
g mol
−
1
, which means that you're going to have to convert the mass of the sample from milligrams to grams
1 g
=
10
3
mg
Sodium chloride,
NaCl
, has a molar mass of
58.44 g mol
−
1
, which means that your sample will contain
unit conversion
280.0
mg
⋅
1
g
10
3
mg
⋅
molar mass
1 mole NaCl
58.44
g
=
0.004791 moles NaCl
This means that the molarity of the solution will be
c
=
n
solute
V
solution
c
=
0.004791 moles
2.00
⋅
10
−
3
L
=
2.40 M
The answer is rounded to three sig figs, the number of sig figs you have for the volume of the solution.
Answer:
Violet is my favorite colour i think its so pretty
Explanation:
Your so nice
From the reaction of ammonia and sulfuric acid in aqueous solution
2nh3(aq)+h2so4(aq)<span>→</span> (NH4)2SO4 + H2O
will be formed.Sulfuric acid is diprotic so is able to give up 2 H+ ions.
It is an acid-base neutralisation reaction forming ammonium sulphate as the salt.
2NH3 with H2SO4 reacts in a neutralization reaction to form salt water, with ammonium sulphate left behind to crystallize after evaporation.
