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zhenek [66]
3 years ago
10

HELP PlEASE

Chemistry
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

1 Polymer

2 Aluminum

3 Hydrocarbons

4 monomers

5 their functional group

6 polyethylene

Explanation:

i took the test

hoa [83]3 years ago
3 0

Answer:Question# 1) Polymer

Question # 2) Aluminum

Question #3) Hydrocarbons

Question # 4) monomers

Question # 5) their functional group

Question # 6) polyethylene

Explanation:

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Why is the periodic table such a brilliant piece of work? Explain and give two reasons.​
Aleksandr-060686 [28]

Answer:

Because it keeps track of all the elements

6 0
3 years ago
Se requieren preparar 1500 ml de una solución al 55% en masa de hidróxido de calcio, sabiendo que la densidad de dicha solución
Masja [62]

Respuesta:

968 g Ca(OH)₂

Explicación:

Paso 1: Calcular la masa de solución

Tenemos 1500 mL de una solución cuya densidad es 1.17 g/mL, es decir, 1 mL de solución tiene una masa de 1.17 g.

1500 mL × 1.17 g/mL = 1.76 × 10³ g

Paso 2: Calcular la masa de hidróxido de calcio en 1.76 × 10³ g de solución

La solución tiene una concentración de 55% en masa de hidróxido de calcio, es decir, cada 100 gramos de solución hay 55 gramos de hidróxido de calcio.

1.76 × 10³ g Solución × 55 g Ca(OH)₂/100 g Solución = 968 g Ca(OH)₂

6 0
3 years ago
If you know any of them that helps!
WARRIOR [948]

Answer:

for the how to get a carrot to float you would need to make a hole in it and make it hollow

Explanation:

6 0
3 years ago
Which substance has a mass is 13.5 grams, and its volume is 5 cm 3.
solmaris [256]

Answer:

Substance is Aluminium

Explanation:

We are given;

Mass; m = 13.5 grams

Volume; V = 5 cm³

Formula for density is;

density = m/V

Density = 13.5/5

Density = 2.7 g/cm³

From the table attached, we can see that the element with a corresponding density of 2.7 is Aluminium

5 0
3 years ago
0.350 mol of a solid was dissolved in 260 mL of water at 21.2 oC. After the solid had fully dissolved, the final temperature of
Fittoniya [83]

Answer: Heat of the solution  = mass water × specific heat water × change in temperature

mass water = 260ml (1.00g/ml ) = 260g

specific heat of water = c(water) = 4.184J/ g°C

Heat change of water = final temperature - initial temperature

                                       = 26.5 - 21.2

                                        = 5.3 °C

H = 260 g ( 4.184J/g°C ) (5.3°C) = 5765J

Molar heat = \frac{5765J}{0.350mol}

                    = 16473J/mol

Explanation: finding molar heat requires first to look at  specific heat of water and the change of water temperature

7 0
3 years ago
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