Complete the blank with the correct answer choice. 3 meters = ________ millimeters A. 30 B. 300 C. 3,000 D. 30,000

As we know that water molecules have been randomly arranged. So when a negatively charged rod is put near the stream of water, the molecules present in the water start rotating, unless the positive side will be close to the negative side of the rod. Which results in the generation of the attraction force. Hence, the stream of the water forces away the negatively charged rod. When the water molecules have polarized molecules in it the effect will be stronger than the dust.

3 0

3 years ago

A 46.2 mL,0.568 M calcium nitrate solution is mixed with 80.5mL of 1.396M calcium nitrate solution.Calculate tge concentration o

Ne4ueva [31]

Answer:

1.09 M

Explanation:

Let's define the equation that will be used to calculate the final concentration of the resultant calcium nitrate solution. In order to calculate it, we need to find the total number of moles of calcium nitrate and divide by the total volume of the resultant solution:

$c=\frac{n}{V}$

This equation firstly helps us find the number of moles of calcium nitrate. Multiplying molarity by volume will yield the moles. Adding the moles from the first component to the second component will provide us with the total number of moles of calcium nitrate:

$n_{Ca(NO_3)_2}=46.2 mL\cdot0.568 M+80.5 mL\cdot1.396 M=138.62 mmol$

Now, the total volume of this solution can be found by adding the volume values of each component:

$V_total=46.2 mL+80.5 mL=126.7 mL$

Finally, dividing the moles found by the total volume will yield the final molarity:

$c_{final}=\frac{138.62 mmol}{126.7 mL}= 1.09 M$

6 0

3 years ago

Calculate the mass ratio of S to O in SO, and then calculate the mass ratio of S to O in SO2, given that the mass of S is approx

ziro4ka [17]

Explanation:

From the knowledge of law of multiple proportions,

mass ratio of S to O in SO:

mass of S : mass of O

= 32 : 16

= 32/16

= 2/1

mass ratio of S to O in SO2:

= mass of S : 2 × mass of O

= 32 : 2 × 16

= 32/32

= 1/1

ratio of mass ratio of S to O in SO to mass ratio of S to O in SO2:

= 2/1 ÷ 1/1

= 2

Thus, the S to O mass ratio in SO is twice the S to O mass ratio in SO2.

8 0

3 years ago