Complete the blank with the correct answer choice. 3 meters = ________ millimeters A. 30 B. 300 C. 3,000 D. 30,000
1 answer:
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Answer:
0.011 mol/L
Explanation:
This can be solved with something called an ICE table.
I = initial
C = change
E = equilibrium
Initially, there is 0.04 M of N₂, 0.04 M of O₂, and 0 M of NO.
x amount of N₂ reacts. Since the stoichiometry is 1:1, x amount of O₂ also reacts. This produces 2x of NO.
After the reaction, there is 0.04-x of N₂, 0.04-x of O₂, and 2x of NO.
Here it is in table form:
Now we can use the equilibrium constant:
Kc = [NO]² / ( [N₂] [O₂] )
Substituting:
0.10 = (2x)² / ( (0.04 - x) (0.04 - x) )
Solving:
0.10 = (2x)² / (0.04 - x)²
√0.10 = 2x / (0.04 - x)
(√0.10) (0.04 - x) = 2x
(√0.10)(0.04) - (√0.10)x = 2x
(√0.10)(0.04) = 2x + (√0.10)x
(√0.10)(0.04) = (2 + √0.10)x
x = (√0.10)(0.04) / (2 + √0.10)
x = 0.0055
At equilibrium, the concentration of NO is 2x. So the answer is:
[NO] = 2x
[NO] = 0.011
The equilibrium concentration of NO is 0.011 mol/L.
Answer:
Limiting reactant: Oxygen
Explanation:
First write the balanced chemical equation:
given mass of methane =25g
molecular mass of methane=16g/mol
mole=1.5625mol
given mass of oxygen=50
molar mass of oxygen=32g/mol
mole=1.5625mol
from the above balanced equation it is clearly that,
1 mole of methane needs 2 moles of oxygen for complete reaction
Therefore,
1.5625 moles of methane needs 3.125 moles of oxygen for complete reaction but we have only 1.5625 moles of oxygen,
hence,
oxygen will be the limiting reactant and methane will be the excess reactant
Answer: moles
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to molecular mass , occupies 22.4 L at STP and contains avogadro's number of particles.
To calculate the moles, we use the equation:
Given mass of ethanol = 0.2301
Molar mass of ethanol = 46.07 g/mol
Thus there are moles of ethanol are present in the sample.