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MAVERICK [17]
2 years ago
12

If the Large Hadron Collider is 27 km long, and visible light travels 3.0 × 108 m/s, how long does it take a ray of visible ligh

t to travel from one end of the collider to the other?
Chemistry
2 answers:
marysya [2.9K]2 years ago
8 0

Answer:

C) 9.0 x 10^-5 s

Valentin [98]2 years ago
6 0
27 km = 27000m. Time = distance/speed = 27000/3x10^8 = 9x10^-5 s. 
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Answer:

A

Explanation:

bc inorganic compoud refers to all compound that do not contain carbons.

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3 years ago
. Who was the scientist responsible for the laws of motion?
Gennadij [26K]

Newton was the scientist

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The average kinetic energy of gas particles depends on which factor?
saveliy_v [14]
Only the temperature of gas
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3 years ago
What volume would 312g of alcohol occupy
Aleksandr-060686 [28]

Answer:

Density=Mass/volume

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Explanation:

3 0
3 years ago
A 0.964 gram sample of a mixture of sodium formate and sodium chloride is analyzed by adding sulfuric acid. The equation for the
frosja888 [35]

Answer: 67.8 %.

Explanation:

Okay, let us delve right into the solution to the question;

The balanced chemical reaction is given by the equation (1) below;

2 HCOONa + H2SO4 ---------> 2 CO + 2 H2O + Na2SO4. ----------------------------------------------------------------------------(1).

From the balanced chemical reaction in equation (1) above we can see that; 2 moles of HCOONa reacts with one moles of tetraoxosulphate acid, H2SO4 to produce 2 moles of carbonmonoxide,CO; 2 moles of water, H2O and 1 mole of sodium tetraoxosulphate, Na2SO4.

The parameters given from the question are; total atmospheric pressure, P(t) = 752 torr, volume of CO= 242 mL = 0.242 Litres.

STEP ONE : find the carbon monoxide,CO pressure; P(CO).

Using the formula below;

P(t) = P(CO) + P(H2O). Hence;

P(CO) = P(t) - P(H2O). Note that P(H2O)= 19.8 torr.

==>P(CO)= 752 torr - 19.8 torr = 732.2 torr.

STEP TWO: calculate the number of moles of Carbonmonoxide,CO.

Using the formula below;

Number of moles= pressure(P) × volume(v) / gas constant(R) × temperature (T).

That is, n= PV/RT.

n= 732 torr × 0.242 Litres/ 62.4 × 295.15.

= 9.62 × 10^-3 mol of CO.

STEP THREE:

2 moles of HCOONa = 2 moles of CO.

=> 2 moles of HCOONa = 2 moles of CO/ 2 moles of CO = 1 mol( HCOONa/ CO).

Then, 9.62 × 10^-3 mol of CO × 1 mol( HCOONa/ CO).

==> 9.62 × 10^-3 mol HCOONa × molar masss of HCOONa(68 grams/mol)

= 0.654 grams.

Therefore, the percentage of sodium formate in the original mixture = 0.654 grams/ 0.964 gram × 100 = 67.8 %.

5 0
3 years ago
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