Answer:
E = 16.464 J
Explanation:
Given that,
Mass of tetherball, m = 0.8 kg
It is hit by a child and rises 2.1 m above the ground, h = 21. m
We need to find the maximum gravitational potential energy of the ball. The formula for the gravitational potential energy is given by :
E = mgh
g is acceleration due to gravity
E = 0.8 kg × 9.8 m/s² × 2.1 m
= 16.464 J
So, the maximum potential energy of the ball is 16.464 J.
Part A:
( 5,000 : 100 ) * 6 = 300 lit.
300 lit. * 1.066 Euros/ lit. = 318.9 Euros
1 Euro = 1.20 USD
318.9 * 1.20 = 382.68 USD
Part B :
6 lit./100 km = 0.06 lit/1 km
1 gal = 3.7853 lit.
1 mile = 1.609344 km
0.06 : 3.7853 = 0.01585
... = 0.01585 gal / 1 km / * 1.609344
= 0.0255 gal/mile
Answer:
Explanation:
one end of tank will be circular in shape . Area of circle A
= π r² , r is radius of the circle
= 3.14 x 3²
A = 28.26 ft³
To calculate force on the circular area , we first find pressure at the center of the circle which is at depth equal to r
pressure at the center = h d g ' here h = depth = r , d = density of milk
pressure = 3 x 64.6 x 32 poundal / ft²
= 6201.6 poundal / ft²
total force on circular face = pressure at the center x area of circle
= 6201.6 x 28.26
= 175257.21 poundal .
Answer:
33.516 kJ
Explanation:
Potential energy is given by:
PE = mgh
Where m is the mass, g is acceleration due to gravity, and h is the height. In this case:
PE = 38kg x 9.8m/s^2 x 90m = 33516 kg m^2/s^2 = 33516 J = 33.516 kJ
