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slega [8]
4 years ago
6

What is one way to induce an electric current

Physics
1 answer:
Lorico [155]4 years ago
8 0
<span>1.an electric is induced when you move a magnet through a coil wire

2.a greater electric current is induced if you add more loops of wire</span>
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Statistical time division multiplexing does not require the capacity of the circuit to be equal to the sum of the combined circu
aleksklad [387]

Answer:

The answer is True

Explanation:

Statistical Multiplexing is considered an example of communication link sharing which makes it comparable to DBA (Dynamic Bandwidth Allocation). Here, communication channels are broken down into data streams to optimize the communication process.

In Statistical Time-division Multiplexing, time slots are allocated to data streams for communication optimization. This method makes sure that no time slot or bandwidth is wasted.

Hence, the sum of combined circuits must not be equal to the capacity of the circuit to work effectively.

7 0
3 years ago
A man stands on top of a cliff and shouts.
satela [25.4K]

\small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x

\small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return =  \frac{2x}{v}  = 1

\bf \to \: x =  \frac{320}{2} m = 160m

\small \bf \: thus \: the \: distance \: between \: the \: cliffs \:  = 160m \times 2 = 320m

8 0
3 years ago
The resistance is 5 Ω and the amount of electric current is 2 A. This means that the amount of voltage is
Hatshy [7]

Answer:

I=2A

R=5

Explanation:

formula

V=IR

=2x5

Voltage=10 volt

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

3 0
3 years ago
A woman can lift barrels a vertical distance of 1 meter or can roll them up a 2-meter long ramp to the same elevation. If she us
olchik [2.2K]

Answer:

answer is 1/2 as much force required

8 0
3 years ago
A 0.49 m copper rod with a mass of 0.15 kg carries a current of 13 A in the positive y direction. Let upward be the positive dir
Helen [10]

Answer:

Magnetic field, B = 0.23 T          

Explanation:

Given that,

Length of the copper rod, L = 0.49 m

Mass of the copper rod, m = 0.15 kg

Current in rod, I = 13 A (in +ve y direction)

When the rod is placed in magnetic field, the magnetic force is balanced by its weight such that :

BIL=mg\\\\B=\dfrac{mg}{IL}\\\\B=\dfrac{0.15\times 9.8}{13\times 0.49}\\\\B=0.23\ T

So, the magnitude of the minimum magnetic field needed to levitate the rod is 0.23 T.

6 0
3 years ago
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