Answer:
14.85 m/s
Explanation:
From the question given above, the following data were obtained:
Height (h) of tower = 45 m
Horizontal distance (s) moved by the balloon = 45 m
Horizontal velocity (u) =?
Next, we shall determine the time taken for the balloon to hit the shoe of the passerby. This is illustrated below:
Height (h) of tower = 45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
45 = ½ × 9.8 × t²
45 = 4.8 × t²
Divide both side by 4.9
t² = 45/4.9
Take the square root of both side
t = √(45/4.9)
t = 3.03 s
Finally, we shall determine the magnitude of the horizontal velocity of the balloon as shown below:
Horizontal distance (s) moved by the balloon = 45 m
Time (t) = 3.03 s
Horizontal velocity (u) =?
s = ut
45 = u × 3.03
Divide both side by 3.03
u = 45/3.03
u = 14.85 m/s
Thus, the magnitude of the horizontal velocity of the balloon was 14.85 m/s
Explanation:
Value of the cross-sectional area is as follows.
A = 
= 3.45 
The given data is as follows.
Allowable stress = 14,500 psi
Shear stress = 7100 psi
Now, we will calculate maximum load from allowable stress as follows.
= 
= 50025 lb
Now, maximum load from shear stress is as follows.
= 
= 48990 lb
Hence, 
will be calculated as follows.
= 48990 lb
Thus, we can conclude that the maximum permissible load is 48990 lb.
I am pretty sure the answer to your question is B
Answer:
I think it has to do something with their ionizations... not entirely sure though.
Explanation:
Answer:
Explanation:
The magnetic field produced by a current-carrying wire is given by
where
is the vacuum permeability
I is the current
r is the distance from the wire
In this problem we have
r = 1.2 mm = 0.0012 m
So the magnetic field strength is
