What is the solution for the gravitational pull on earth?

1 answer:

8 0

The magnitude of the force of gravity pulling on an object located on Earth is

(9.8 meters per second²) x (the mass of the object in kilograms).

The direction of the force is toward the center of the Earth.

The unit for the magnitude of the force is [ Newton ].

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If you add together all of forces exerted on an object and get a non zero value this is called the _____ force on the object

butalik [34]

Your answer would be the; <u>NET</u> force on the object. Refer to Newton's Laws of Forces and Motion.

Hope that helps!!!!!!!!!!!!!!!! : )

8 0

3 years ago

Read 2 more answers

The smallest unit of charge is − 1.6 × 10 − 19 C, which is the charge in coulombs of a single electron. Robert Millikan was able

vovangra [49]

Answer:

$-8.0 \times 10 ^{-19 }\ C,\ -3.2 \times 10 ^{-19 }\ C, -4.8 \times 10 ^{-19 }\ C$

Explanation:

<u>Charge of an Electron</u>

Since Robert Millikan determined the charge of a single electron is

$q_e=-1.6\cdot 10^{-19}\ C$

Every possible charged particle must have a charge that is an exact multiple of that elemental charge. For example, if a particle has 5 electrons in excess, thus its charge is $5\times -1.6\cdot 10^{-19}\ C=-8 \cdot 10^{-19}\ C$

Let's test the possible charges listed in the question:

$-8.0 \times 10 ^{-19 }$ . We have just found it's a possible charge of a particle

$-3.2 \times 10 ^{-19 }$ . Since 3.2 is an exact multiple of 1.6, this is also a possible charge of the oil droplets

$-1.2 \times 10 ^{-19 }$ this is not a possible charge for an oil droplet since it's smaller than the charge of the electron, the smallest unit of charge