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kozerog [31]
3 years ago
8

what actually is left over of water once it self ionizes? Like what exactly are the hydrogen and hydroxide ions? Do they remain

a liquid?
Chemistry
1 answer:
GrogVix [38]3 years ago
5 0
The formula for the self ionization of water is 2H₂O(l)⇄H₃O⁺(aq)+OH⁻(aq)

The hydronium (H₃O⁺) is usually just referred to as a hydrogen ion or a proton (H⁺) and hydroxide (OH⁻) doesn't have another name that I am aware of.  These ions do stay in solution.  However the concentrations are really small and the equilibrium constant (K(w)) is 1×10⁻¹⁴.

I hope this helps.  Let me know if anything is unclear.
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a sample of ammonia liberates 5.66 kj of heat as it solidifies at its melting point . what is the mass of the sample?
Reil [10]
The correct answer for the question that is being presented above is this one: "<span>16.728 g."</span>

Given that 
ΔHsolid = -5.66 kJ/mol.
This means that 5.66 kJ of heat is released when 1 mole of NH3 solidifies 

When 5.57 kJ of heat is released
amount of NH3 solidifies = 5.57/5.66 = 0.984 moles 

<span>molar mass of NH3 = 17 g/mole </span>
<span>1 mole of NH3 = 17 g </span>
So, 0.984 moles of NH3 = 17 X 0.984 = 16.728 g
7 0
3 years ago
During electrophilic aromatic substitution, a resonance-stabilized cation intermediate is formed. Groups, already present on the
DIA [1.3K]

Answer:

See explanation and image attached

Explanation:

Aromatic compounds undergo electrophilic aromatic substitution reactions in which the aromatic ring is maintained.

Substituted benzenes may be more or less reactive towards electrophilic aromatic substitution than benzene depending on the nature of the substituent present in the ring.

Substituents that activate the ring towards electrophilic substitution such as -OCH3 are ortho-para directing.

The major products of the bromination of anisole are p-bromoanisole and o-bromoanisole. The resonance structures leading to these products are shown in the image attached.

5 0
3 years ago
After balancing the following reaction under acidic conditions, how many mole equivalents of water are required and on which sid
nordsb [41]

Answer:

d. 8 moles of H2O on the product side

Explanation:

Hello,

In this case, we need to balance the given redox reaction in acidic media as shown below:

MnO_4^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O\\\\2Cl^{1-}\rightarrow Cl_2^0+2e^-\\\\2*[(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O]\\\\5*[2Cl^{1-}\rightarrow Cl_2^0+2e^-]\\\\\\\\2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O\\\\10Cl^{1-}\rightarrow 5Cl_2^0+10e^-\\

Then, we add the half reactions:

2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10Cl^{1-} \rightarrow 2Mn^{2+}+8H_2O+5Cl_2^0

Thereby, we can see d. 8 moles of H2O on the product side.

Best regards.

4 0
2 years ago
methane is a flammable compound made of carbon and hydrogen atoms. how could you seperate the carbon and hydrogen in methane
sergiy2304 [10]
As we know methane is an Alkane to separate an Alkane We use fractional distillation to put each liquid into its fraction with the right temperature group
7 0
3 years ago
What are the solutions to the equation x2 + 4x + 5 = 0?​
dusya [7]

Answer:

-1, -4

Explanation:

x^2+4x+5=0

Factoring, you get:

(x+4)(x+1)=0

To find what x can be, you need to realize what could make this equation true. To set the left side equal to 0, either one of the terms in parentheses must be equal to 0. To do that, x must be the negative of the other term, so that they can cancel each other out. Therefore, x is -4 and -1. Hope this helps!

4 0
2 years ago
Read 2 more answers
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