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3 years ago

Carbon, hydrogen, silicon, nitrogen, sulfur, and phosphorus are the six most important elements found in living things.

1 answer:

8 0

<span>false

All organic compounds in nature have one molecule that is common in all of them, namely carbon.</span>An organic compound is any member of a large group of compounds which may be gaseous, liquid, or solid that have molecules containing carbon.Organic compounds are the basis of earth's carbon cycle through which biogeochemical processes ensure that carbon moves from living to non living systems and back again.Examples of organic compounds include proteins, carbohydrates, lipids, nucleic acids, diamond and graphite.
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You might be interested in

How many moles are in 5.6x1025 molecules of calcium oxide?

Vlad1618 [11]

Answer:

<h2>93.02 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{5.6 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 93.023...$

We have the final answer as

<h3>93.02 moles</h3>

Hope this helps you

8 0

3 years ago

13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What

rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

<em>of MgCO3.3H2O in the mixture?</em>

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

<em>Mass water:</em>

3.883g - 2.927g = 0.956g water

<em>Moles water -18.01g/mol-</em>

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

<em>Moles MgCO3.3H2O:</em>

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

<em>Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-</em>

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

<em>Mass percent:</em>

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

6 0

3 years ago

What is the factor of 1024

Ugo [173]

1
2
4
8
16
32
64
128
256
512
1024

4 0

3 years ago

86.14 mL of an acid solution was needed to neutralize 30.24 mL of a base solution of unknown concentrations. A second trial is r

Airida [17]

Answer:

The correct answer is option B.

Explanation:

As given ,that 30.24 mL of base was neutralize by 86.14 mL of acid which means that moles of base present in 30.24 mL are neutralized by moles of acid present in 86.14 mL.

After dilution of base from 30.24 mL to 50.0 mL .Since, the moles of base are same in the solution as that of the moles in solution before dilution. Moles of acid require to neutralize the base after dilution will same as a that of present moles of acid present in 86.14 mL.

5 0

3 years ago

In a certain variety of plants, red flowers appear in majority of plants and blue flowers appear only in a few plants. Which sta

Jlenok [28]

Answer:

Explanation:

3 0

3 years ago