3 years ago

What is the ph of a 0.027 M KOH solution?

1 answer:

8 0

First you calculate the concentration of [OH⁻] in <span>solution :

POH = - log [ OH</span>⁻]

POH = - log [ 0.027 ]

POH = 1.56

PH + POH = 14

PH + 1.56 = 14

PH = 14 - 1.56

PH = 12.44

hope this helps!

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