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aalyn [17]
3 years ago
14

when the concentration of hydrogen ions in a solution is decreased by a factor of ten, the pH of the solution

Chemistry
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

Increases by 1

Explanation:

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Which best explains why ionization energy tends to decrease from the top to the bottom of a group? The number of orbitals decrea
cluponka [151]

Answer:

Electrons get farther from the nucleus.

Explanation:

By going from the top to the bottom of a group, the atomic number increases. That would mean that:

  • The number of orbitals increases, as there are more electrons.
  • A higher atomic number implies an increasing number of neutrons.
  • As there are more electrons, they get farther from the nucleus. The farther an electron is from the nucleus, the easier it is for the electron to be removed from the atom.
4 0
3 years ago
Two___ of the element sodium combine with one___ of the element chlorine to form the ___ sodium chloride
Evgen [1.6K]

Answer:

third, fourth

Explanation:

7 0
2 years ago
When N2(g) reacts with H2(g) to form NH3(g), 92.2 kJ of energy are evolved for each mole of N2(g) that reacts. Write a balanced
Naddika [18.5K]

Answer:

N₂ + 3H₂ → 2NH₃   ΔH = - 92.2KJ

Explanation:

Let's write out the chemical equation between Nitrogen and Hydrogen to Form Ammonia.

Nitrogen + Hydrogen = Ammonia

N₂ + H₂ → NH₃

A Thermochemical Equation is a balanced stoichiometric chemical equation that includes the enthalpy change, ΔH.

The balanced stoichiometric chemical equation is given as;

N₂ + 3H₂ → 2NH₃

92.2 kJ of energy are evolved for each mole of N2(g) that reacts. And from the equation, 1 mole of N2 reacts.

The enthalpy change, ΔH = - 92.2KJ. The negative sign is because heat is being evolved.

The balanced thermochemical equation;

N₂ + 3H₂ → 2NH₃   ΔH = - 92.2KJ

6 0
3 years ago
Which of the following solutions is more concentrated?<br> 0.50M KCl or 5.0% (w/v) KCl
HACTEHA [7]

.50 M KCl because 5% is the same as .05, which makes the .50M more concentrated.

6 0
3 years ago
A rubber balloon was filled with helium at 25.0˚C and placed in a beaker of liquid nitrogen at -196.0˚C. The volume of the cold
Ksenya-84 [330]

Answer:

The volume of helium at 25.0 °C is 60.3 cm³.

Explanation:

In order to work with ideal gases we need to consider absolute temperatures (Kelvin). To convert Celsius to Kelvin we use the following expression:

K = °C + 273.15

The initial and final temperatures are:

T₁ = 25.0 + 273.15 = 298.2 K

T₂ = -196.0 + 273.15 = 77.2 K

The volume at 77.2 K is V₂ = 15.6 cm³. To calculate V₁ in isobaric conditions we can use Charle's Law.

\frac{V_{1}}{T_{1}} =\frac{V_{2}}{T_{2}} \\V_{1}=\frac{V_{2}}{T_{2}} \times T_{1}=\frac{15.6cm^{3} }{77.2K} \times 298.2K=60.3cm^{3}

3 0
3 years ago
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