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3 years ago

Explain the reaction between metallic hydroxides and a dilute acid?

1 answer:

7 0

The hydroxide (OH) in the metallic hydroxide will react with the hydrogen in an acid to form H2O. The remaining ions will combine to form a salt. Therefore a metal hydroxide and an acid will form a salt + water.

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In the following reaction, which are the products?

myrzilka [38]

Answer: H2 + MgCl2

Explanation: As they are on the right side of the equation/ are the products being made as a result of the reaction, they are the products.

5 0

3 years ago

3. (05.04 MC)

Alex73 [517]

Answer:

1.10 g H2

Explanation:

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3 years ago

Which of the following occurs during a redox reaction?

GenaCL600 [577]

Answer:

C = Electrons are won and lost.

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining and losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O → CO₂ + H₂

the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

3 0

3 years ago

"My breasts are really sensitive, and depending on when my partner touches them, this can make or break a pleasure session. What

dem82 [27]

Answer:

Where do I even start?

Explanation:

4 0

3 years ago

What is the activity coefficient of H in a solution containing 0.073 M HCl and 0.0090 M Ca(ClO4)2? A table of activity coefficie

yarga [219]

Answer:

The value is $pH = 1.22$

Explanation:

From the question we are told that

The concentration of $H^{+}$ is $[H^{+}] = 0.073 \ M$

The concentration of $Cl^{-}$ is $[Cl{+}] = 0.073 \ M$

The concentration of $Ca^{+}$ is $[Ca{2+}] = 0.0090 \ M$

The concentration of $ClO^{-}$ is $[ClO^{-}] = 2 *0.0090 = 0.018$

Generally the log of the activity coefficient is mathematically represented as

$log \ \gamma__{H^+}} = \frac{-0.5z^2 * \sqrt{\mu} }{1 + (\alpha * \frac{\sqrt{\mu}}{305} )}$

Here z is the charge which for $H^{+}$ is +1

$\alpha$ is the size which for $H^{+}$ is $900pm = 900*10^{-12} \ m$

$\mu$ is the ionic strength which is mathematically represented as

$\mu = \frac{1}{2} * \{ 0.073* (+1)^2 +0.073 * (-1)^2+0.0090 * (+2)^2+ 0.018* (-1)^2 \}$

=> $\mu = 0.1$

$log \ \gamma__{H^+}} = \frac{-0.5(+1)^2 * \sqrt{0.1} }{1 + (900*10^{-12} * \frac{\sqrt{0.1}}{305} )}$

=> $log \ \gamma_{H^+} = -0.083$

=> $\gamma__{H^+}} = antilog(-0.083)$

=> $\gamma__{H^+}} =0.82$

Generally the pH is mathematically represented as

$pH = -log [H^{+}] * \gamma__{H^{+}}$

$pH = -log 0.073 * 0.82$

=> $pH = 1.22$

3 0

3 years ago