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sattari [20]
3 years ago
6

92 grams of ethanol,C2H5OH, is dissolved in 1 liter of solution. Determine the molarity (M)

Chemistry
1 answer:
const2013 [10]3 years ago
4 0

Answer:  1.997 M

Explanation:

molarity = moles of solute/liters of solution or M = \frac{mol}{L}

first we have to find our moles of solute (mol), which you can find by dividing the mass of solute by molar mass of solute

mass of solute: 92 g

molar mass of solute: 46.08 g/mol

let's plug it in:

\frac{92 g}{46.08 g/mol} = 1.997 mol

next, we plug it into our original equation:

\frac{1.997mol}{1 L} = 1.997 M

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3 years ago
A solution is prepared by dissolving 318.6 g sucrose (C12H22O11) in 4905 g of water. Determine the molarity of the solution
alexandr1967 [171]

The molarity of sucrose solution is 0.19 M.

The molarity of HCl is 12.8 M.

<u>Explanation:</u>

a. Molarity can be found by finding its moles and volume of water in L and then dividing both(moles divided by volume in Litres).

Mass of sucrose = 318. 6 g

Molar mass of sucrose = 342.3 g/mol

Moles = $\frac{mass}{molar mass}

       = $\frac{318.6 g}{342.3 g/mol}

      = 0.93 moles

Mass of water = 4905 g

Density of water = 1000 g/L

Volume = $\frac{mass}{density}

             = $\frac{4905 g }{1000 g/L}

          = 4.905 L

Now we can find the molarity = $\frac{moles}{Volume(L)}

                               =  $\frac{0.93 moles}{4.905 L}

                              = 0.19 M

So the molarity of sucrose solution is 0.19 M.

b. The molarity of HCl can be found as follows.

It is given that 39% HCl that means it contains 39 g of acid in 100 g of water.

Density of the solution is 1.20 g/mL, from this mass can be found as,

$\frac{1 L \times 1000 mL \times 1.20 g}{1 L \times 1 mL}

= 1200 g

Now we have to find out the amount of HCl in grams as,

$\frac{1200g \times 39 g HCl }{100 g solution}

= 468 g HCl

Now we have to find the number of moles,

moles = $\frac{468 g}{36.46 g/mol}

           = 12.8 moles

Molarity of HCl = $\frac{12.8 moles}{1 L }

                          = 12.8 M

So the molarity of HCl is 12.8 M.

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