What is the overall cell potential for this redox reaction?
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<h3>Answer:</h3>
10.6 mol NO
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right<u> </u>
<u>Chemistry</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
[RxN - Balanced] 4NH₃ + 5O₂ → 4NO + 6H₂O
[Given] 13.2 mol O₂
<u>Step 2: Identify Conversions</u>
[RxN] 5 mol O₂ → 4 mol NO
<u>Step 3: Stoich</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
10.56 mol NO ≈ 10.6 mol NO
A 50.0 ml sample of 0.108 m h2so4 is diluted to 250.0 ml. Its new molarity will be 0.0216 m.
Dilution would be the process of lowering a solute's concentration in a solution. It usually just includes combining the solution with much more solvent, such as water. A solution is diluted when more solvent is added without increasing solute.
Molarity can be calculated by using the formula:
where, M is molarity and V is volume.
Given data:
= 0.108 m
= 50 ml
= 250 ml
Put the value of given data in above equation.
0.108 m × 50 ml = M × 250ml
M = 0.0216 m
Therefore, the new molarity will be 0.0216 m.
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