4. Is the mass of the products of a nuclear fission reaction compared to

When 8.0 moles of methanol are reacted with 9.0 moles of oxygen, how many moles of water vapor does the reaction produce?

nadya68 [22]

Answer:

12 moles of H₂O are formed in this combustion.

Explanation:

First of all, think the reaction:

2CH₃OH (l) + 3O₂ (g) → 2CO₂ (g) + 4H₂O (g)

Ratio in the reactants is 2:3, so 2 mol of methanol need 3 mol of oxygen to react. Then 8 mol of CH₃OH, will need (8.3)/2 = 12 moles of O₂

We have 9 moles of O₂, so this is the limiting reactant.

3 mol of oxygen produce 4 mol of water

Then, 9 mol of oxygen will produce ( 9 .4)/3 = 12 moles

3 0

3 years ago

a car is traveling at a speed of 55 mph the speed increased to 75 mph if the time needed to hange its speed is 4 seconds whats t

Savatey [412]

v = 75 mph = 33.52 m/s

u = 55 mph = 24.58 m/s

t = 4 sec

acceleration = v-u/t

= 33.52-24.58/4

= 8.94/4

= 2.235 m/s

6 0

3 years ago

When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M = 163 m/z) is formed.

DanielleElmas [232]

Answer:

As the molecular mass of given amine is 163 g/mol (a odd number) it means that this compound contains a odd number of Nitrogen atoms. We will first apply Rule of Thirteen to get the molecular formula.

Rule of Thirteen:

First divide the parent peak value by 13 as,

= 163 ÷ 13

= 12.53

Now, multiply 13 by 12,

= 13 × 12 (here, 12 specifies number of carbon atoms)

= 156

Now subtract 156 from 163,

= 163 - 156

= 7

Add 7 into 12,

= 7 + 12

= 19 (hydrogen atoms)

So, the rough formula we have is,

C₁₂H₁₉

Now, add one Nitrogen atom to above formula and subtract one Carbon and 2 Hydrogen atoms as these numbers are equal to atomic mass of Nitrogen atom as,

C₁₂H₁₉ -------N--------> C₁₁H₁₇N

Also, as shown in ¹³C-NMR there is one peak around 180 ppm and the peak at 1661 cm⁻¹ in IR spectrum is characteristic to carbonyl group hence, we will add one oxygen atom to the chemical formula accordingly. i.e.

C₁₁H₁₇N -------O--------> C₁₀H₁₃NO

Molecular Formula: C₁₀H₁₃NO

Also,

In NMR the the four peaks around 120 ppm are assigned to a mono substituted benzene ring.

The absence of IR peak above 3200 cm⁻³ also confirms that the amine is tertiary in nature and there is no hydrogen attached to the nitrogen atom.

It can be observed that the peaks in upfield are duplicating. This can be due to the presence of rotamers of said compound.

The most plausible structure for given data is shown below, and the resonance structure along with rotamers are also shown.

6 0

3 years ago

What is the mass of an atom with seven protons, seven neutrons, and eight electrons?

belka [17]

Answer:

14

Explanation:

mass number = protons + neutrons

6 0

3 years ago

Strike anywhere matches contain the compound tetraphosphorus trisulfide, which burns to form tetraphosphorus decaoxide and sulfu

erica [24]

Answer:

194.6 mL of SO₂

Explanation:

The reaction that takes place is:

P₄S₃ + 6O₂(g) → P₄O₁₀ + 3SO₂(g)

<u>To solve this problem we need to use PV=nRT</u>, so first let's convert the given units:

23.8 °C → 23.8 + 273.15 = 296.95 K

747 torr → 747/760 = 0.983 atm

We need to calculate V, so in order to do that we calculate n, using the mass of the reactant (P₄S₃):

0.576 g P₄S₃ * $\frac{1molP_{4}S_{3}}{220gP_{4}S_{3}} *\frac{3molSO_{2}}{1molP_{4}S_{3}}$ = 7.85 * 10⁻³ mol SO₂ = n

Now we calculate V:

PV=nRT

0.983 atm * V = 7.85 * 10⁻³ mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.95 K

V = 0.1946 L

Finally we convert L into mL:

0.1946 * 1000 = 194.6 mL

8 0

3 years ago