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GrogVix [38]
2 years ago
7

What net force would be needed to accelerate a 2.95kg bowling ball at 6.25m/s^2?

Physics
1 answer:
aksik [14]2 years ago
3 0
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A 600kg car is moving at 5 m/s to the right and elastically collided with a stationary 900 kg car. What is the velocity of the 9
11111nata11111 [884]

Answer:

\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}

Explanation:

It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.

m_{1} v_{1}=m_{2} v_{2}

\mathrm{m}_{1} \text { and } \mathrm{m}_{2} \text { are masses of the object }

\mathrm{v}_{1} \text { velocity before the collision }

\mathrm{v}_{2} \text { velocity after the collision }

\mathrm{m}_{1}=600 \mathrm{kg}

\mathrm{m}_{2}=900 \mathrm{kg}

\text { Velocity before the collision } v_{1}=5 \mathrm{m} / \mathrm{s}

600 \times 5=900 \times v_{2}

3000=900 \times v_{2}

\mathrm{v}_{2}=\frac{3000}{900}

\mathrm{v}_{2}=3.3 \mathrm{m} / \mathrm{s}

\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}

5 0
3 years ago
There are stars located in the center bulge of the Milky Way and the spiral arms of the Milky Way. What is the difference betwee
nadya68 [22]

Answer:

The stars at the center bulge are bigger and brighter than the stars in the arms.

Explanation:

5 0
3 years ago
How does increasing the tension of a spring affect a wave on the spring?
Liono4ka [1.6K]
More energy is being used in the movement

8 0
3 years ago
Read 2 more answers
Two parakeets sit on a swing with their combined center of mass 10.0 cm below the pivot. At what frequency do they swing?
Oksanka [162]

Answer:

1.58 Hz

Explanation:

The frequency of the simple pendulum is given by

f = 1/T

 = 1/2π√g/l  

In this problem, I = 10.0 cm = 0.1 m  

f = 1/2π√9.8/0.1

=  1.58 Hz

7 0
3 years ago
Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 77.3 N, Jill pull
DiKsa [7]

Answer:

F_{net} = 232.8 N

towards right so it is -15 degree

Explanation:

Net force in forward direction due to all three is given as

F_x = F_1 + F_2cos45 + F_3cos45

here we know that

F_1 = 77.3 N

F_2 = 61.7 N

F_3 = 147 N

F_x = 77.3 + 61.7 cos45 + 147 cos45

F_x = 224.9 N

Similarly in Y direction we will have

F_y = F_3 sin45 - F_2 sin45

F_y = (147 - 61.7)sin45

F_y = 60.3 N

Now the net force on the donkey is given as

F_{net} = \sqrt{F_x^2 + F_y^2}

F_{net} = \sqrt{224.9^2 + 60.3^2}

F_{net} = 232.8 N

Now direction of force is given as

tan\theta = \frac{F_y}{F_x}

tan\theta = \frac{60.3}{224.9}

\theta = 15^o towards right so it is -15 degree

3 0
3 years ago
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