Answer:
Electric potential = 0.00054 V
Explanation:
We are given;
Charge; q = 3 pC = 3 × 10^(-12) C
Radius; r = 2 cm = 0.02 m
Formula for the electric potential of this surface will be;
V = kqr
Where;
K is a constant = 9 × 10^(9) N⋅m²/C².
Thus;
V = 9 × 10^(9) × 3 × 10^(-12) × 0.02
V = 0.00054 V
Answer:
C. outside 45 degrees
Step-by-step explanation:
C. outside 45 degrees
because it can be any point or direction outside 45 degrees
Answer:
particle's potential energy = 70J
Explanation:
From conservation of energy; K1 + Ue1 = K2 + Ue2
where K1 and K2 are the kinetic energies at two positions and Ue1 and Uue2 are the electrical potential energies at two positions.
k1 = 10J, Ue1 = 100J
K2 = 40J
substitute into K1 + Ue1 = K2 + Ue2
Ue2 = K1 + Ue1 - K2
= 10 +100 - 40
Ue2 = 70J
Answer:
The acceleration is 0.
Explanation:
The formula for acceleration is:
a = (v-u)/t
If v and u are equal, thus it would be 0 when subtracted, and anything divided by 0 is 0.
Answer:
Explanation:
The distance travelled in the free fall is H - h
Since the apple originally started from rest we can use v^2 = u^2 + 2 x g x s where v is the final velocity, g the accln due to gravity and s the distance travelled and u is the initial velocity = 0
So the velocity just before it enters the grass is sq rt [2 x g x (H - h)]
Once in the grass, it slows down at a constant rate which means that the acceleration (a) during this period is constant.
So once again using the same formula we have v = O and u = sq rt[2 x g x (H-h)]
so since v^2 = u^2 + 2 x a x s then
O^2 = 2 x g x (H-h) + 2 x a x h
{O^2 - 2 x g x (H - h)}/(2 x h) = a
