Given that,
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.
To find,
The distance from the source would the sound level be one-fourth the sound level at 3.00 m.
Solution,
The intensity from a source is inversely proportional to the distance.
Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?
Using relation :
So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.
Answer:
Cost = $ 7.72
Explanation:
Considering the trip of 100 km, the cost spent on the fuel during the trip can be calculated by the following formula:
where,
Average Fuel Consumption = 6 liter/100 km
Unit Fuel Cost = (1.063 euros/liter)($ 1.21/1 euro) = $ 1.29/liter
Distance = 100 km
Therefore,
<u>Cost = $ 7.72</u>
Answer:
15.8 N
Explanation:
The component in a given direction is the magnitude of the applied force, multiplied by the cosine of the angle between its application and the direction of interest.
The horizontal component is ...
(20 N)cos(38°) ≈ 15.8 N
Answer:
2 secs; 65 feet
Explanation:
The function guiding the water bottle is given as:
f(x) = -16t² + 64t + 1
The bottle will reach maximum height when velocity, df/dt (velocity is the first derivative of distance) = 0.
Therefore:
df/dt = 0 = -32t + 64
=> 32t = 64
t = 64/32 = 2 seconds
This is the time it will take to reach the maximum height.
To find this height, we insert t = 2 into the function f(x):
f = -16(2)² + 64(2) + 1
f = -(16 * 4) + 128 + 1
f = -64 + 128 + 1
f = 65 ft
Its maximum height is 65 ft.