All categories

3 years ago

Which statements about the moon’s phases are true? Check all that apply.

Physics

2 answers:

patriot [66]3 years ago

7 0

Answer:

The same side of the moon always faces the earth

A new moon occurs when the Sun shines on the side of the moon not facing Earth.

A full moon happens when the Earth is between the Sun and the moon.

Explanation:

I just did the test

nikklg [1K]3 years ago

3 0

Answer:

A,C,F

1,3,6

Explanation:

You might be interested in

Which floor type had the least amount of friction?

MArishka [77]

the answer is a. bc carpet has lot and tile has more than gravel

5 0

3 years ago

Read 2 more answers

James (mass 95.0 kg ) and Ramon (mass 67.0 kg ) are 20.0 m apart on a frozen pond. Midway between them is a mug of their favorit

SOVA2 [1]

Answer:

The speed of James is 0.776 m/s

Explanation:

Step 1: Data given

mass of James = 95.0 kg

mass of Ramon = 67.0 kg

We consider James and Ramon and the rope to a single system. This means that the net external forces on the system = 0

.The momentum = 0, so the sum of the momentum of each part must be 0 in total.

Step 2: Calculate the speed of James

m(james) *v(James) = m(Ramon) * v(Ramon)

with m(James) = the mass of James = 95.0 kg

with v(James) = speed of James = TO BE DETERMINED

with m(Ramon) = mass of Ramon = 67.0 kg

with v(Ramon) = speed of Ramon = 1.10 m/s

v(James) = (m(Ramon) * v(Ramon))/ m(james)

v(James) = (67.0 kg* 1.10 m/s) / 95.0 kg

v(James) = 0.776 m/s

The speed of James is 0.776 m/s

8 0

3 years ago

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics

lianna [129]

<h2>Answer:</h2>

<em><u>Velocity of throwing arrow = 43.13 m/s.</u></em>

<h2>Explanation:</h2>

In the question,

Let us say the height from which the arrow was shot = h

Distance traveled by the arrow in horizontal = 61 m

Angle made by the arrow with the ground = 2°

So,

From the <u>equations of the motion</u>,

$61 =u.t\\t=\frac{61}{u}$

Now,

Also,

Finally, the angle made is 2 degrees with the horizontal.

So,

Final horizontal velocity = v.cos20°

Final vertical velocity = v.sin20°

Now,

u = v.cos20° (No acceleration in horizontal)

Also,

$v=u+at\\vsin20=0+9.8(t)\\t=\frac{v.sin20}{9.8}$

So,

We can say that,

$\frac{v.sin20}{9.8}=\frac{61}{v.cos20}\\v^{2}.sin20.cos20=597.8\\v^{2}=1860.56\\v=43.13\,m/s$

<em><u>Therefore, the velocity with which the arrow was shot by the archer is 43.13 m/s.</u></em>

5 0

3 years ago

Which information about the earth would not be represented when a globe is used as a model?

egoroff_w [7]

A globe sitting on the desk can't demonstrate the speed of axial rotation
or the speed of orbital revolution.

5 0

3 years ago

As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. Th

NikAS [45]

Answer:

M = 0.730*m

V = 0.663*v

Explanation:

Data Given:

$v_{bullet, initial} = v\\v_{bullet, final} = 0.516*v\\v_{paper, initial} = 0\\v_{paper, final} = V\\mass_{bullet} = m\\mass_{paper} = M\\Loss Ek = 0.413 Ek$

Conservation of Momentum:

$P_{initial} = P_{final}\\m*v_{i} = m*0.516v_{i} + M*V\\0.484m*v_{i} = M*V .... Eq1$

Energy Balance:

$\frac{1}{2}*m*v^2_{i} = \frac{1}{2}*m*(0.516v_{i})^2 + \frac{1}{2}*M*V^2 + 0.413*\frac{1}{2}*m*v^2_{i}\\\\0.320744*m*v^2_{i} = M*V^2\\\\M = \frac{0.320744*m*v^2_{i} }{V^2} ....... Eq 2$

Substitute Eq 2 into Eq 1

$0.484*m*v_{i} = \frac{0.320744*m*v^2_{i} }{V^2} *V \\0.484 = 0.320744*\frac{v_{i} }{V} \\\\V = 0.663*v_{i}$

Using Eq 1

$0.484m*v_{i} = M* 0.663v_{i}\\\\M = 0.730*m$

7 0

3 years ago