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3 years ago

Which statements about the moon’s phases are true? Check all that apply.

Physics

2 answers:

patriot [66]3 years ago

7 0

Answer:

The same side of the moon always faces the earth

A new moon occurs when the Sun shines on the side of the moon not facing Earth.

A full moon happens when the Earth is between the Sun and the moon.

Explanation:

I just did the test

nikklg [1K]3 years ago

3 0

Answer:

A,C,F

1,3,6

Explanation:

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A 100 N force is applied to a 500 kg crate resting on frictionless wheels.

Alla [95]

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{100}{500} = \frac{1}{5} = 0.2 \\$

We have the final answer as

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2 years ago

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aev [14]

The bulb

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3 years ago

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White raven [17]

When these bonds are destroyed, a reaction occurs. ... Vinegar reacting with limestone breaks the bonds of calcium carbonate and acetic acid.

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3 years ago

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Salsk061 [2.6K]

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3 years ago

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A car of mass m accelerates from speed v_1 to speed v_2 while going up a slope that makes an angle theta with the horizontal. Th

Karo-lina-s [1.5K]

Answer:

Work done by external force is given as

$Work_{external} = mgLsin\theta + \mu mgLcos(\theta) + \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$

Explanation:

As per work energy Theorem we can say that work done by all force on the car is equal to change in kinetic energy of the car

so we will have

$Work_{external} + Work_{gravity} + Work_{friction} = \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$

now we have

$W_{gravity} = -mg(Lsin\theta)$

$W_{friction} = -\mu mgcos(\theta) L$

so from above equation

$Work_{external} - mgLsin\theta - \mu mgLcos(\theta) = \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$

so from above equation work done by external force is given as

$Work_{external} = mgLsin\theta + \mu mgLcos(\theta) + \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$

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3 years ago