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zmey [24]
3 years ago
12

Which statements about the moon’s phases are true? Check all that apply.

Physics
2 answers:
patriot [66]3 years ago
7 0

Answer:

The same side of the moon always faces the earth

A new moon occurs when the Sun shines on the side of the moon not facing Earth.

A full moon happens when the Earth is between the Sun and the moon.

Explanation:

I just did the test

nikklg [1K]3 years ago
3 0

Answer:

A,C,F

1,3,6

Explanation:

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A step up transformer has 250 turns on its primary and 500 turns on it secondary. When the primary is connected to a 200 V and t
Zina [86]

Answer:

2000 W

Explanation:

First of all, we need to find the output voltage in the transformer, by using the transformer equation:

\frac{V_1}{N_1}=\frac{V_2}{N_2}

where here we have

V1 = 200 V is the voltage in the primary coil

V2 is the voltage in the secondary coil

N1 = 250 is the number of turns in the primary coil

N2 = 500 is the number of turns in the secondary coil

Solving for V2,

V_2 = N_2 \frac{V_1}{N_1}=(500) \frac{200 V}{250}=400 V

Now we can find the power output, which is given by

P = VI

where

V = 400 V is the output voltage

I = 5 A is the output current

Substituting,

P = (400 V)(5 A) = 2,000 W

3 0
4 years ago
A horizontal pull A pulls two wagons over a horizontal frictionless floor, the first wagon is 500N, the second is 2000 N. The te
MrMuchimi
<span>The force will be zero if the wagons are moving at a constant speed (i.e. not accelerating), as there is no frictional force to overcome. If the wagons are accelerating, the force will be proportional to the acceleration, and 20% of the force applied by A.</span>
5 0
4 years ago
PLEASE HELP!!! which of these would represent the force of gravity?
Vladimir [108]
Force D.
Gravity points downward.
6 0
3 years ago
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A sled is dragged along a horizontal path at a constant speed of 1.50 m/s by a rope that is inclined at an angle of 30.0° with r
Allisa [31]

Answer:2987.7 J

Explanation:

Given

sled weight is W=470 N

Tension in rope T=230 N

Time interval t=10 s

velocity of sled v=1.5 m/s

here speed is equal to velocity which is constant therefore acceleration is zero

thus F_{net}=0

Distance traveled in t=10 s

x=v\times t=1.5\times 10=15 m

considering surface to be friction less

thus T\cos 30 will do work on sled

W=F\cdot x

W=T\cos 30\cdot x

W=230\cos 30\times 15

W=2987.78 J\approx 2.987 kJ

4 0
4 years ago
All of the following are ways in which electromagnetic waves are measured except
valkas [14]
I think its c. velocity.    pretty sure
7 0
3 years ago
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