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Furkat [3]
3 years ago
15

A hole of radius r is bored through the center of a sphere of radius r. Find the volume v of the remaining portion of the sphere

.
Physics
2 answers:
zhannawk [14.2K]3 years ago
6 0

Answer:

V=πr^2(4r/3-h), where h will be the diameter of the sphere, V=-(2πr^3)/3

Explanation:

nikklg [1K]3 years ago
5 0

Answer:

Πr²(4r/3 - h)

Explanation:

Volume of a sphere is 4/3Πr³. If a hole of radius r is bored through, the hole with generate a circular shape in the sphere. The volume of the remaining portion of the sphere will be the difference between the volume of the sphere and the area of the hole bored(which will be volume of a cylinder since the hole bored will create a cylindrical shape in the sphere)

Area of the remaining portion = Volume of sphere - volume of a cylinder

Volume of sphere = 4/3Πr³

Volume of a cylinder = Πr²h

Volume of the remaining portion = 4/3Πr³ - Πr²h

= Πr²(4r/3 - h)

Where h is the height of the cylindrical hole

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artcher [175]

Answer:

F=m*g is the formula and the answer is 19,620 kg

Explanation:

Since the formula is F=m*g and Earth's gravity is 9.81 m/s^2 all you need to do is multiply 2,000 by 9.81

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Two of the types of infrared light, ir-c and ir-a, are both components of sunlight. their wavelengths range from 3000 to 1,000,0
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The energy of a light wave is calculated using the formula
E = hc/λ
h is the Planck's constant
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For the ir-c, the range is
<span>6.63 x 10^-34 (3x10^8) / 3000 = 6.63 x 10 ^-29 J
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For the ir-a, the range is
6.63 x 10^-34 (3x10^8) / 700 = 2.84 x 10^-28 J
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What happens when the data in an investigation does not support the origanal hypothesis
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Answer: The scientist gives up and starts an investigation on a new topic.

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The data is altered so that it supports the original hypothesized. The data is then altered so that it supports the original hypothesis.

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If you started the motor of a boat in the middle of a lake, who would detect the sound of the motor first: a friend sitting on t
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A friend snorkeling just below the surface of the water along the same shore will detect the sound first.

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A 125-kg astronaut (including space suit) acquires a speed of 2.50 m/s by pushing off with her legs from a 1900-kg space capsule
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p_i = 0

The final total momentum is instead:

p_f = m_a v_a + m_c v_c

where

m_a = 125 kg is the mass of the astronaut

v_a = 2.50 m/s is the velocity of the astronaut

m_c = 1900 kg is the mass of the capsule

v_c is the velocity of the capsule

Since the total momentum must be conserved, we have

p_i = p_f = 0

so

m_a v_a + m_c v_c=0

Solving the equation for v_c, we find

v_c = - \frac{m_a v_a}{m_c}=-\frac{(125 kg)(2.50 m/s)}{1900 kg}=-0.165 m/s

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So, the change in speed of the capsule is 0.165 m/s.

(b) 520.8 N

We can calculate the average force exerted by the capsule on the man by using the impulse theorem, which states that the product between the average force and the time of the collision is equal to the change in momentum of the astronaut:

F \Delta t = \Delta p

The change in momentum of the astronaut is

\Delta p= m\Delta v = (125 kg)(2.50 m/s)=312.5 kg m/s

And the duration of the push is

\Delta t = 0.600 s

So re-arranging the equation we find the average force exerted by the capsule on the astronaut:

F=\frac{\Delta p}{\Delta t}=\frac{312.5 kg m/s}{0.600 s}=520.8 N

And according to Newton's third law, the astronaut exerts an equal and opposite force on the capsule.

(c) 25.9 J, 390.6 J

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

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m is the mass

v is the speed

For the astronaut, m = 125 kg and v = 2.50 m/s, so its kinetic energy is

K=\frac{1}{2}(125 kg)(2.50 m/s)^2=390.6 J

For the capsule, m = 1900 kg and v = 0.165 m/s, so its kinetic energy is

K=\frac{1}{2}(1900 kg)(0.165 m/s)^2=25.9 J

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