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kupik [55]
3 years ago
8

The space shuttle usually orbited Earth at altitudes of around 300.0 km. 1) Determine the time for one orbit of the shuttle abou

t Earth. (Express your answer to three significant figures.) h You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2) How many sunrises per day did the astronauts witness
Physics
1 answer:
777dan777 [17]3 years ago
3 0

Answer:

Explanation:

distance of shuttle from centre of the earth = radius of the orbit

= 6300 + 300 = 6600 km

= 6600 x 10³

Formula of time period of the satellite

T = 2π R /v₀ , v₀ is orbital velocity

v₀ = √gR , ( if height  is small with respect to radius )

T = 2π R /√gR

= 2π√ R /√g

= 2 x 3.14 x √ 6600 x 10³ / √9.8

= 2 x 3.14 x 256.9 x 10 / 3.13

= 5154.41 s

= 5154.41 / 60 minutes

= 85.91 m

85.9 minutes.

2 ) No of sunrise per day = no of rotation per day

= 24 x 60 / 85.9

= 16.76

or 17 sunrises.

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Answer:

True

Explanation:

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What is the instantaneous speed of the monkey at time t=5s?
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What is the acceleration of a 10 kg mass pushed by a 5 N force
hichkok12 [17]

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2 years ago
How do boron-10 and boron-11 differ?
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2 years ago
A ball is thrown w a speed of 30m/s at an angle of 10. When is the vertical component of the velocity equal to zero
irga5000 [103]

Now the vertical velocity of the ball thrown at an angle 10° is given as

Voy(initial vertical velocity)= 30m/s x sin 10

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Let Vy be the final velocity and that is equal to zero in this case.

Now

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Substituting the values we get

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t=0.53 secs



5 0
2 years ago
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