Answer:
20
To10
Explanation:
Which statement gives the gradient of this gr
Answer:
The correct option is (A).
Explanation:
The direction of electric force is in the direction of electric field. The electric force acting on a charged particle is given by :
F = qE, q is magnitude of charge
We have, a negative test charge experiences a force to the right as a result of an electric field. It would mean that the electric field points to the left because the force on a negative charge is opposite to the direction of the field.
Answer:
elastic partial width is 2.49 eV
Explanation:
given data
ER E = 250 eV
spin J = 0
cross-section magnitude σ = 1300 barns
peak P = 20ev
to find out
elastic partial width W
solution
we know here that
σ = λ²× W / ( E × π × P ) ...................1
put here all value
σ = (0.286)² × W × / ( 250 × π × 20 )
1300 × = (0.286)² × W × / ( 250 × π × 20 )
solve it and we get W
W = 249.56 ×
so elastic partial width is 2.49 eV
As per the question there are two physical quantities i.e scalar quantity and vector quantity.
A scalar is a physical quantity which requires only magnitude.It does not require any direction for it's complete specification.For instance we may take distance travelled,speed etc.
Unlike a scalar quantity,a vector quantity requires both magnitude as well as direction for it's complete specifications.For instance we may take displacement which is the shortest distance between two points,the velocity which is the speed in a given direction.
Hence a vector and scalar is differentiated by direction.
As per the question,the correct option will be the third option i.e C.
Carlita is right.As per her, both vector and scalar have magnitude,but only vectors have direction which is also true.
Answer:
The electrical energy is 13.5 kWh or 48600 kJ
Explanation:
Given that,
The power of the resistance heater, P = 4.5 kW
The water heater runs for 3 hours to raise the water temperature to the desired level.
We need to find the amount of electric energy used in both kWh and kJ.
Energy = Power × time
E = 4.5 kW × 3 h
= 13.5 kWh
Since,
1 kWh = 3600 kJ
13.5 kWh = 48600 kJ
Hence, the required electrical energy is 13.5 kWh or 48600 kJ