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Oliga [24]
3 years ago
9

Use the drop-down menu to complete the statement. One difference between prokaryotic cells and eukaryotic cells is that a eukary

otic cell contains , while a prokaryotic cell does not.
Physics
1 answer:
Ahat [919]3 years ago
8 0

Answer:

Nucleus

Explanation: I did the quiz and got it right. Have an amazing day!

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If a person is near sighted what type of lens will their glass have to correct their eyesight
oksian1 [2.3K]

Answer:

Since the nearsighted eye over converges light rays, the correction for nearsightedness is to place a diverging spectacle lens in front of the eye. This reduces the power of an eye that is too powerful.

Explanation:

7 0
3 years ago
Read 2 more answers
You are driving your car, and the traffic light ahead turns red. you apply the brakes for 2.26 s, and the velocity of the car de
Lorico [155]

Let the initial velocity of the car be u.

Final velocity of the car (v) = 5.43 m/s

deceleration (a) = - 2.78 m/s^2

Time taken (t) = 2.26 s

Using the first equation of motion:

v = u + at

u = v - at

u = 5.43 - (-2.78 \times 2.26)

u = 5.43 + 6.28

u = 11.71 m/s

Let the car's displacement be x.

Using second equation of motion:

x = ut + \frac{1}{2}at^2

x = 11.71 \times 2.26 - \frac{1}{2} \times 2.78 \times 2.26^2

x = 26.4646 - 7.0995

x = 19.3651 meters

Hence, the displacement of the car is 19.36 meters

6 0
3 years ago
Which of the following is true about a combustion reaction?
Ksenya-84 [330]

Answer:

b

Explanation:

this is because inoder. for combustion or burning to take place oxygen must be available

7 0
3 years ago
a sphere with a radius of 8cm carries a uniform volume charge density of 1.5 find the magnitude of the electric field
gladu [14]

Answer:

E = 5.65 x 10¹⁰ N/C

Explanation:

First we need to find the total charge on the sphere. So, we use the following formula for that purpose:

q = \sigma V\\

where,

q = total charge on sphere

V = Volume of Sphere = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (0.08\ m)^3 =  0.335\ m^3

σ = volume charge density = 1.5 C/m³

Therefore,

q = (0.335\ m^3)(1.5\ C/m^3) \\q = 0.502 C

Now, we use the following formula to find the electric field due to this charged sphere:

E = \frac{kq}{r^2}

where.

E  = Electric Field Magnitude = ?

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

r = radius of sphere = 8 cm = 0.08 m

Therefore,

E = \frac{(9\ x\ 10^9\ Nm^2/C^2)(0.502 C)}{(0.08\ m)^2}\\\\

<u>E = 5.65 x 10¹⁰ N/C</u>

5 0
3 years ago
The rate of rotation of the disk is gradually increased. The coefficient of static friction between the coin and the disk is 0.5
MrRissso [65]

Question is not complete and the missing part is;

A coin of mass 0.0050 kg is placed on a horizontal disk at a distance of 0.14 m from the center. The disk rotates at a constant rate in a counterclockwise direction. The coin does not slip, and the time it takes for the coin to make a complete revolution is 1.5 s.

Answer:

0.828 m/s

Explanation:

Resolving vertically, we have;

Fn and Fg act vertically. Thus,

Fn - Fg = 0 - - - - eq(1)

Resolving horizontally, we have;

Ff = ma - - - - eq(2)

Now, Fn and Fg are both mg and both will cancel out in eq 1.

Leaving us with eq 2.

So, Ff = ma

Now, Frictional force: Ff = μmg where μ is coefficient of friction.

Also, a = v²/r

Where v is linear speed or velocity

Thus,

μmg = mv²/r

m will cancel out,

Thus, μg = v²/r

Making v the subject;

rμg = v²

v = √rμg

Plugging in the relevant values,

v = √0.14 x 0.5 x 9.8

v = √0.686

v = 0.828 m/s

3 0
3 years ago
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