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Vlad1618 [11]
4 years ago
11

Lori’s family is on a road trip. They split their drive into the five legs listed in the table. Find the average velocity for ea

ch leg of the trip. Then arrange the legs of the trip from lowest velocity to highest.
Physics
1 answer:
PIT_PIT [208]4 years ago
3 0
Average velocity is displacement  divided by time elapsed; Δv/Δt

You will need to use the information in the table you are given. Subtract: (final velocity - initial velocity) and divide by (final time - initial time).
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What type of elastic force is present in the strings on a guitar?
jeyben [28]
B) Tension , is the correct answer
4 0
3 years ago
A professor sits on a rotating stool that is spinning at 10.0 rpm while she holds a heavy weight in each of her hands. Her outst
MAVERICK [17]

Answer:

0.5864 m

Explanation:

r_1 = 0.705 m

\omega_1 = 10 rpm

\omega_2 = 20.5 rpm

\left(m r_{1}^{2}\right) \omega_{1} &=\left(m r_{2}^{2}\right) \omega_{2}

r_{2}^{2} &=\frac{\left(m r_{1}^{2}\right) \omega_{1}}{\left(\omega_{2}\right)}

=\frac{\left(r_{1}^{2}\right) \omega_{1}}{\left(\omega_{2}\right)}

=\frac{\left((0.705 \mathrm{m})^{2}\right)(10 \mathrm{rpm})}{(20.5 \mathrm{rpm})}

=\sqrt{\frac{\left((0.705 \mathrm{m})^{2}\right)(10 \mathrm{rpm})}{(20.5 \mathrm{rpm})}}

r_{2} =0.5864\ m

The weights are 0.5864 m apart.

7 0
4 years ago
How much ice (at 0°C) must be added to 1.90 kg of water at 79 °C so as to end up with all liquid at 8 °C? (ci = 2000 J/(kg.°
muminat

m = mass of the ice added = ?

M = mass of water = 1.90 kg

c_{w} = specific heat of the water = 4186 J/(kg ⁰C)

c_{i}  = specific heat of the ice = 2000 J/(kg ⁰C)

L_{f} = latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg

T_{ii}  = initial temperature of ice = 0 ⁰C

T_{wi} = initial temperature of water = 79 ⁰C

T = final equilibrium temperature = 8 ⁰C

using conservation of heat

Heat gained by ice = Heat lost by water

m c_{w}  (T - T_{ii} ) + m L_{f}  = M c_{w}  (T_{wi} - T)

inserting the values

m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)

m = 1.53 kg

4 0
3 years ago
a Porsche 911 accelerates from rest to 27 metre per second due north in 5.8 seconds the mass of the car is 1400 kg what is the m
user100 [1]

Answer:

The average force has a magnitude 6524 N due north.

Explanation:

The average net force F = ma where m = mass of car = 1400 kg and a = acceleration.

a = (v - u)/t where u = initial velocity of car = 0 m/s (since it starts from rest)

v = final velocity of car = 27 m/s due north and t = time of motion = 5.8 s

a = (27 m/s - 0 m/s)/5.8 s = 27 m/s ÷ 5.8 s = 4.66 m/s

Since the direction of the velocity change is the direction of the acceleration, the acceleration is 4.66 m/s due north.

The average force, F = ma = 1400 kg × 4.66 m/s = 6524 N

Since the acceleration is due north, the average force takes the direction of the acceleration.

So the direction of the average force is due north

The average force has a magnitude 6524 N due north.

7 0
3 years ago
Calculate the voltage difference in a circuit with a resistance of 25 Ω if the current in the circuit is 0.5 A.
weeeeeb [17]

Answer:

check the attachments for the solution

8 0
2 years ago
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