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4 years ago

5

Two moles of He gas are at 25 degrees C and a pressure of 210 kPa. If the gas is heated to 48 degrees C and its pressure reduced

to 37 % of its initial value, what is the new volume?

1 answer:

SpyIntel [72]4 years ago

4 0

Answer: $0.0686 m^3$

Explanation:

Given

No of moles=2

$T=25^{\circ}\approx 298 K$

$P_1=210 KPa$

$T_2=48 ^{\circ}\approx 321 k$

$P_2=77.7 KPa$

PV=nRT

Substitute

$77.7\times V_2=2\times 8.314\times 321$

$V_2=0.0686 m^3$

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3 years ago

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When three people with a total mass of 2.00 x 102 kg step into their 1.200 x 103 kg car, the car’s

Aleksandr-060686 [28]

Answer:

a

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b

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Explanation:

From the question we are told that

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The mass of the car is $m_c = 1.200 *10^{3} \ kg$

The compression of the car spring is $x = 3 \ cm = 0.03 \ m$

Generally the spring constant is mathematically represented as

$k = \frac{F}{x}$

Here F is the force exerted by the mass of three people and that of the car , this is mathematically represented as

=> $F = (M +m_c) *g$

=> $F = ([2.0*10^{2} ]+[ 1.200*10^{3}]) * 9.8$

=> $F = 13720 \ N$

So

$k = \frac{13720}{0.03}$

=> $k = 457333.3 N/m$

Generally if the mass which the car is loaded with is $m = 3.00*10^{2} \ kg$

Then the force experienced by the spring is

=> $F_a = (m +m_c) *g$

=> $F_a = (3.00*10^{3} + 1.200 *10^{3}) * 9.8$

=> $F_a = 41160 \ N$

Generally from the above formula the compression is

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3 years ago

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Sergio039 [100]

Answer:

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Explanation:

∑F = ma

kx cos θ = ma

x = ma / (k cos θ)

x = (10 kg) (5 m/s²) / (70 N/m cos 30.0°)

x = 0.824 m

x = 82.4 cm

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According to Hooke's Law formula. The force is proportional to the displacement of the spring. I believe

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To make a given sound seem twice as loud, how should a musician change the intensity of the sound?

Serhud [2]

Answer:

C. Quadruple the intensity

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The intensity of the sound is proportional to square of amplitude of the sound.

I ∝ A²

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A₂ = 2A₁

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Thus, to make a given sound seem twice as loud, the musician should Quadruple the intensity

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