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yaroslaw [1]
3 years ago
5

Two moles of He gas are at 25 degrees C and a pressure of 210 kPa. If the gas is heated to 48 degrees C and its pressure reduced

to 37 % of its initial value, what is the new volume?
Physics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:0.0686 m^3

Explanation:

Given

No of moles=2

T=25^{\circ}\approx 298 K

P_1=210 KPa

T_2=48 ^{\circ}\approx 321 k

P_2=77.7 KPa

PV=nRT

Substitute

77.7\times V_2=2\times 8.314\times 321

V_2=0.0686 m^3

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amid [387]

Answer:

The magnitude of the net force is √2F.

Explanation:

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F_N=\sqrt{F^{2}+F^{2}}\\\\F_N=\sqrt{2F^{2}}\\\\F_N=\sqrt{2}F

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3 years ago
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A 5 kgkg sphere having a charge of ++ 8 μCμC is placed on a scale, which measures its weight in newtons. A second sphere having
Mrac [35]

Answer:

 F_Balance = 46.6 N    ,m' = 4,755 kg

Explanation:

In this exercise, when the sphere is placed on the balance, it indicates the weight of the sphere, when another sphere of opposite charge is placed, they are attracted so that the balance reading decreases, resulting in

          ∑ F = 0

          Fe –W + F_Balance = 0

         F_Balance = - Fe + W

           

The electric force is given by Coulomb's law

          Fe = k q₁ q₂ / r₂

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           F_Balance = mg - k q₁q₂ / r₂

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          r = 0.3 m = 0.3 m

Let's calculate

         F_Balance = 5 9.8 - 8.99 10⁹  8 10⁻⁶ 3 10⁻⁶ / (0.3)²

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This is the balance reading, if it is calibrated in kg, it must be divided by the value of the gravity acceleration.

Mass reading is

          m' = F_Balance / g

          m' = 46.6 /9.8

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