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yaroslaw [1]
3 years ago
5

Two moles of He gas are at 25 degrees C and a pressure of 210 kPa. If the gas is heated to 48 degrees C and its pressure reduced

to 37 % of its initial value, what is the new volume?
Physics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:0.0686 m^3

Explanation:

Given

No of moles=2

T=25^{\circ}\approx 298 K

P_1=210 KPa

T_2=48 ^{\circ}\approx 321 k

P_2=77.7 KPa

PV=nRT

Substitute

77.7\times V_2=2\times 8.314\times 321

V_2=0.0686 m^3

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