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kotykmax [81]
3 years ago
5

Two charged objects are separated by some distance. the charge on the first object is greater than the charge on the second obje

ct. how does the force between the two objects compare?
Physics
2 answers:
oksian1 [2.3K]3 years ago
8 0
Force will be compared by coulomb law


M12 = M21
Svetlanka [38]3 years ago
7 0
The forces in both directions are equal. Their strength depends on the PRODUCT of the charges, not on their individual values or the comparison between them. Same goes for gravity. Your weight on Earth is exactly the same as the Earth's weight on YOU.
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A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
AfilCa [17]
First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)
3 0
3 years ago
If two firecrackers produce a sound level 85dB. What level does the explosion of one firecracker produce?
mars1129 [50]

Level of sound is related to intensity by this equation

L = 10 Log \frac{I}{I_o}

given that

L = 85 dB

also we know that

I_o = 10^{-12} W/m^2

now we have

85 = 10 Log \frac{I}{10^{-12}}

By solving above equation

I = 10^{8.5} * 10^{-12}

I = 3.16 * 10^{-4} W/m^2

now above is the intensity due to two firecrackers and if we wish to find the sound level of one firecracker then we will find its half level intensity

I_1 = \frac{I}{2}

I_1 = 1.58 * 10^{-4}

now again by above formula

L = 10 Log \frac{1.58 * 10^{-4}}{10^{-12}}

L = 82 dB

8 0
3 years ago
The reaction mixture represented above is at equilibrium at 298 K. The value of the equilibrium constant for the reaction is 16
andre [41]

Answer : The equilibrium concentration of T(g) is 0.5 M

Solution :

Let us assume that the equilibrium reaction be:

The given equilibrium reaction is,

R(g)+2T(g)\rightleftharpoons 2X(g)+Z(g)

The expression of K_c will be,

K_c=\frac{[Z][X]^2}{[R][T]^2}

where,

K_c = equilibrium constant = 16

[Z] = concentration of Z at equilibrium = 2.0 M

[R] = concentration of R at equilibrium = 2.0 M

[X] = concentration of X at equilibrium = 2.0 M

[T] = concentration of T at equilibrium = ?

Now put all the given values in the above expression, we get:

16=\frac{(2.0)\times (2.0)^2}{(2.0)\times [T]^2}

[T]=0.5M

Therefore, the equilibrium concentration of T(g) is 0.5 M

8 0
4 years ago
A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.1 cm/min. At what rate is the volume of
andrew11 [14]

Answer:

\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}

Explanation:

Knowing that the volume of a sphere is V=(4/3)πr³ and \frac{dr}{dt}=-0.1\frac{cm}{min}

We must find \frac{dV}{dt}=? when r=14cm

V=(4/3)πr³ ⇒

\frac{dV}{dt}=\frac{4}{3}\pi3r^{2}\frac{dr}{dt}\\\frac{dV}{dt}=4\pi r^{2}(-0.1\frac{cm}{min})

and r=14cm then

\frac{dV}{dt}=4\pi(14cm)^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=4\pi196cm^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}

Note: as you can see the relationship of change of r with respect to t is negative because it is a decrease, and also its volume ratio

4 0
4 years ago
Which of the following is an example of speed?
Arturiano [62]
The cat has a speed. The truck and the bicycle both have velocity. We can't be sure of what the plane has.
6 0
3 years ago
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