Two charged objects are separated by some distance. the charge on the first object is greater than the charge on the second obje
2 answers:
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Explanation:
It is given that,
Mass of the brick, m = 1.15 kg
Radius of the circle, r = 1.44 m
The cable will break if the tension exceeds 43.0 N
Let v is the maximum sped can have at the bottom of the circle before the cable will break. At the bottom of the circle, the net force is equal to the centripetal force along with the weight of the brick. So,
v = 6.30 m/s
So, the maximum speed of the brick at the bottom of the circle before the cable will break is 6.3 m/s. Hence, this is the required solution.
Answer: 2.67 m/s
Explanation:
Given
Mass of block A is
mass of block B is
The initial velocity of block A
the initial velocity of block B is
After collision velocity of block A is
Conserving momentum
The momentum of block A after the collision is
Therefore, there is no change in sign.