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VashaNatasha [74]
4 years ago
6

A net force of 3000 N is accelerating a 1200 kg elevator upward. If the elevator starts from rest, how long will it take to trav

el up 15 m?
Physics
1 answer:
alexdok [17]4 years ago
5 0

F = net force acting on the elevator in upward direction = 3000 N

m = mass of the elevator = 1200 kg

a = acceleration of the elevator = ?

Acceleration of the elevator is given as

a = F/m

a = 3000/1200

a = 2.5 m/s²

v₀ = initial velocity of the elevator = 0 m/s

Y = displacement of the elevator = 15 m

t = time taken

Using the kinematics equation

Y = v₀ t + (0.5) a t²

15 = (0) t + (0.5) (2.5) t²

t = 3.5 sec

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(a) Then the momentum of each vehicle can be obtained by the product of mass with their respective speed.

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Similarly, the momentum of car will be

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(b) Since, after collision, the vehicles stick together, the momentum after collision will be equal to the total momentum of both the vehicles before collision. This is because, it will obey conservation of momentum.

Momentum of vehicles after collision = total momentum before collision

Momentum after collision = 80000+13500 = 93500 kgm/s.

The direction of the vehicles after collision will be towards south as the mass and speed of the truck is greater than car. So the impact or force exerted on the car by the truck will be greater and thus both the vehicles will be directed towards south after collision.

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Answer:

Explanation:

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change  in the gravitational potential energy of the bear-Earth system during the slide  = mgh

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c ) If  the average frictional force that acts on the sliding bear be F

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Answer:

The sound intensity of train is 1000 times greater than that of the library.

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