What type of force pulls in two opposite directions?

Physics

2 answers:

torisob [31]3 years ago

7 0

Tensional forces which is associated with normal faults

Keith_Richards [23]3 years ago

6 0

Answer:

A. tension (associated with normal faults)

Explanation:

Given that force is an action that modifies the resting state of a body; therefore, it can accelerate or modify the speed, direction or direction of movement of a given body and that tension, on the other hand, is the state of a body subjected to the action of opposing forces that attract it, we can affirm that the correct option is A.

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Consider this row in the periodic table of elements. Which element(s) are most likely to conduct electricity?

Sidana [21]

A) lithium and beryllium

Explanation:

From the given row on the periodic table, only lithium and beryllium will conduct electricity.

What makes a substance able to conduct electricity?

The presence of free mobile electrons and in some, ions allows them to carry electric currents.

Metals are generally known to be good conductors of heat and electricity. This is because, metals have a large pool of electrons i.e free mobile electrons. They are electropositive with a large size and readily release their electrons for conduction.

Lithium and Beryllium are in the metallic block on the periodic table.

Learn more:

Metals brainly.com/question/2474874

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6 0

3 years ago

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Learning Goal: To understand the behavior ofthe electric field at the surface of a conductor, and itsrelationship to surface cha

Ivan

Complete Question

The complete question is shown on the first uploaded image

Answer:

a it is always zero

b 0

c $\eta = -\epsilon _o E$

Explanation:ss

Here the net charge is on the outer surface of the conductor thus this means that the net charge inside the conductor is zero

Generally the charge density of a conductor is dependent on the charge per unit area which implies that the charge density is dependent on the net charge so this means that the charge density inside the conductor is zero

Generally the direction of electric field this from the positive charge to the negative charge so from the question we can deduce that the negative charge is located on the surface of the conductor

So We can mathematically define the charge density on the surface of the electric field as

∮ $E \cdot dA = \frac{-Q}{\epsilon _o}$