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Alchen [17]
3 years ago
7

What type of force pulls in two opposite directions?

Physics
2 answers:
torisob [31]3 years ago
7 0
Tensional forces which is associated with normal faults
Keith_Richards [23]3 years ago
6 0

Answer:

A. tension (associated with normal faults)

Explanation:

Given that force is an action that modifies the resting state of a body; therefore, it can accelerate or modify the speed, direction or direction of movement of a given body and that tension, on the other hand, is the state of a body subjected to the action of opposing forces that attract it, we can affirm that the correct option is A.

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White light is an _____________ mixture of all the colors.<br> a) observable b) unequal c) equal
Musya8 [376]

Answer:

unequal

Explanation:

White light is a combination of all colors in the color spectrum.

6 0
3 years ago
Read 2 more answers
1.what is gravity?(in your own words)
olga_2 [115]

Answer:

1.Gravity is an invisible force that pulls objects toward each other

2.The suns gravity pulls the planet towards the sun which changes the straight line of direction into a curve

That keeps the planet moving in an orbit around the sun

hope it helped:)

8 0
2 years ago
the half-life of iodine-131 is 8.1 days. how much time had passed if i only have one-fourth of the original sample?​
morpeh [17]

Answer:

16.2 days

Explanation:

Find the number of halflives:

1/2   *  1/2 =  1/4     so <u>two</u>   halflives have passed

   2 * 8.1 days = 16.2 days

8 0
1 year ago
A copper wire has a radius of 3.5 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o
denpristay [2]

Answer:

The tensile stress on the wire is 550 MPa.

Explanation:

Given;

Radius of copper wire, R = 3.5 mm

extension of the copper wire, e =  5.0×10⁻³ L

L is the original length of the copper wire,

Young's modulus for copper, Y =  11×10¹⁰Pa.

Young's modulus, Y is given as the ratio of tensile stress to tensile strain, measured in the same unit as Young's modulus.

Y =\frac{Tensile \ stress}{Tensile \ strain} \\\\Tensile \ stress = Y*Tensile \ strain\\\\But, Tensile \ strain = \frac{extension}{original \ Length} = \frac{5.0*10^{-3} L}{L} = 5.0*10^{-3}\\\\Tensile \ stress = 11*10^{10} *5.0*10^{-3} \ = 550*10^6 \ Pa

Therefore, the tensile stress on the wire is 550 MPa.

8 0
3 years ago
Using the method of dimension, derive an expression for the velocity of sound waves. assume that the velocitu depends on:
Soloha48 [4]

Answer:

v = K √(E / ρ)

Explanation:

Modulus of elasticity has units of N/m², or kg/m/s².

Density has units of kg/m³.

Velocity has units of m/s.

If we divide modulus of elasticity by density, we can eliminate kg:

E / ρ = [kg/m/s²] / [kg/m³]

E / ρ = [m²/s²]

Taking the square root gets us units of velocity:

√(E / ρ) = [m/s]

Multiply by the constant K:

v = K √(E / ρ)

7 0
3 years ago
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