Answer: the correct answer would be the last option, C6H12O6 and O2
Explanation:
The average atomic mass of her sample is 114.54 amu
Let the 1st isotope be A
Let the 2nd isotope be B
From the question given above, the following data were obtained:
- Abundance of isotope A (A%) = 59.34%
- Mass of isotope A = 113.6459 amu
- Mass of isotope B = 115.8488 amu
- Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
- Average atomic mass =?
The average atomic mass of the sample can be obtained as follow:
![Average \: atomic \: mass \: = \frac{mass \: of \: A \times A\%}{100} + \frac{mass \: of \: B \times B\%}{100} \\ \\ Average \: atomic \: mass \: = \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\ \\ Average \: atomic \: mass \: = 114.54 \: amu \\ \\](https://tex.z-dn.net/?f=Average%20%5C%3A%20atomic%20%5C%3A%20mass%20%5C%3A%20%20%3D%20%20%5Cfrac%7Bmass%20%5C%3A%20of%20%5C%3A%20A%20%5Ctimes%20A%5C%25%7D%7B100%7D%20%20%2B%20%5Cfrac%7Bmass%20%5C%3A%20of%20%5C%3A%20B%20%5Ctimes%20B%5C%25%7D%7B100%7D%20%20%5C%5C%20%20%5C%5C%20Average%20%5C%3A%20atomic%20%5C%3A%20mass%20%5C%3A%20%20%3D%20%20%5Cfrac%7B113.6459%5Ctimes%2059.34%7D%7B100%7D%20%2B%20%5Cfrac%7B115.8488%5Ctimes%2040.66%7D%7B100%7D%20%5C%5C%20%20%5C%5C%20Average%20%5C%3A%20atomic%20%5C%3A%20mass%20%5C%3A%20%20%3D%20114.54%20%5C%3A%20amu%20%20%5C%5C%20%20%5C%5C%20%20)
Thus, the average atomic mass of the sample is 114.54 amu
Learn more about isotope: brainly.com/question/25868336
I would say A and D. A is right for sure, as for D, I'm not so sure. Hope this helps!