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ivolga24 [154]
3 years ago
11

How many electrons are transferred between the cation and anion to form the ionic bond in one formula unit of each compound? (1

electrons, 2 electrons, 3 electrons, 4 electrons) ?NaCICaSBaOKBrLiF
Chemistry
1 answer:
kodGreya [7K]3 years ago
4 0

The number of transferred electrons to form the ionic bond in one formula unit of each compound is as below

NaCl = 1 electron

CaS = 2 electrons

BaO= 2 electrons

KBr=1 electrons

LIF = 1 electron



explanation

ionic bond is formed between a metal and a nonmetal . This bond is formed when electron are transferred between cation and anion. To know how many electrons transferred you look the oxidation state of the metal.


for example 

in NaCl only one electrons is transferred since Na is in oxidation state of +1. Na donate the one electron to Cl to form an ionic bond.  Ba  is in oxidation state  of 2+ and hence it  donate the two electrons to O to form ionic bond.

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Combining a base and an acid forms
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How many moles are in 39.5 grams of Lithium?
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185.05 g.

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From the balanced equation: 2LiCl → 2Li + Cl₂

It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.

We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.

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Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.

Using cross multiplication:

2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.

??? moles of LiCl → 4.365  moles of Li.

The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.

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