Answer:
answer a: a large front gear with a small back gear
answer b: a small front gear with a large back gear
Explanation:
just simple gearing ratios
Answer:
a)W=8.333lbf.ft
b)W=0.0107 Btu.
Explanation:
<u>Complete question</u>
The force F required to compress a spring a distance x is given by F– F0 = kx where k is the spring constant and F0 is the preload. Determine the work required to compress a spring whose spring constant is k= 200 lbf/in a distance of one inch starting from its free length where F0 = 0 lbf. Express your answer in both lbf-ft and Btu.
Solution
Preload = F₀=0 lbf
Spring constant k= 200 lbf/in
Initial length of spring x₁=0
Final length of spring x₂= 1 in
At any point, the force during deflection of a spring is given by;
F= F₀× kx where F₀ initial force, k is spring constant and x is the deflection from original point of the spring.

Change to lbf.ft by dividing the value by 12 because 1ft=12 in
100/12 = 8.333 lbf.ft
work required to compress the spring, W=8.333lbf.ft
The work required to compress the spring in Btu will be;
1 Btu= 778 lbf.ft
?= 8.333 lbf.ft----------------cross multiply
(8.333*1)/ 778 =0.0107 Btu.
<h3><u>Answer;</u></h3>
Kinetic energy
A car engine changes chemical potential energy into the <u>kinetic energy</u> of the moving car.
<h3><u>Explanation;</u></h3>
- A car engine converts potential chemical energy stored in gasoline into thermal energy and then into kinetic mechanical energy.
- When gasoline undergoes combustion it reacts with oxygen to produce carbon dioxide and water vapor.Gasoline is a mixture of octane and similar hydrocarbons and contains potential chemical energy.
- The hot exhaust gases from the combustion of gasoline that are produced within the cylinder expand and exert pressure, moving the piston in the cylinder outward then inward as the gas is exhausted. Kinetic mechanical energy of the moving pistons is transferred to the drive shaft and eventually to the wheels, giving the car kinetic mechanical energy.
Answer:
7200 Joules
Explanation:
Also joules means the SI unit of work or energy, equal to the work done by a force of one newton when its point of application moves one meter in the direction of action of the force, equivalent to one 3600th of a watt-hour.
Answer:
13.4s
Explanation:
t = usinx/g. (X= angle , u= initial velocity)
= (147×sin63)/9.8
=13.4