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3 years ago

Using the equation for force (due to weight) and your mass , calculate your force

Physics

1 answer:

vladimir2022 [97]3 years ago

5 0

The weight of the object is 679.1 N

Explanation:

The weight of an object is given by:

$W=mg$

where

W is the weight

m is the mass of the object

g is the acceleration of gravity

For an object near the Earth's surface, the acceleration of gravity is

$g=9.8 m/s^2$

The mass of the object in this problem is

m = 69.3 kg

Therefore, its weight is

$W=(69.3)(9.8)=679.1 N$

Learn more about weight and forces:

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Older televisions display a picture using a device called a cathode ray tube, where electrons are emitted at high speed and coll

Len [333]

Answer:

Explanation:

initial velocity v = 2.1 x 10⁷ m/s

acceleration a = 5.1 x 10¹⁵ m /s²

horizontal distance covered = 5.5 x 10⁻² m

time taken to cover horizontal distance = 5.5 x 10⁻² / 2.1 x 10⁷

= 2.62 x 10⁻⁹ s .

b )

vertical distance travelled due to vertical acceleration

= 1/2 a t²

= .5 x 5.1 x 10¹⁵ x (2.62 x 10⁻⁹)²

= 17.5 x 10⁻³ m

4 0

3 years ago

Two objects experienced the same displacement in the same amount of time. The two objects must have the same -

nikdorinn [45]

If two object experiences the same displacement at the same time, the two objects must have the same average velocity.

The average velocity of an object is defined as the change in displacement per change in time of motion. This can be written as follows;

$avg. \ velocity = \frac{\Delta \ displacement }{\Delta \ time} \\\\V = \frac{\Delta \ x}{\Delta t}$

If two object experiences the same displacement at the same time, it means that the change in displacement with time is constant.

$\frac{\Delta x_1}{\Delta t_1} = \frac{\Delta x_2}{\Delta t_2} = V_{avg}$

Thus, we can conclude that if two object experiences the same displacement at the same time, the two objects must have the same average velocity.

Learn more here: brainly.com/question/23856383

6 0

3 years ago

98 Points and brainlyest for 5 Science questions please I need it doe before 2:30 ET!!!

Marina CMI [18]

Picture #1:
GPE = (mass) x (gravity) x (height)
GPE = (2 kg) x (9.8 m/s²) x (40 m) = 784 joules

KE = (1/2) (mass) (speed²)
KE = (1/2) (2 kg) (5 m/s)²
KE = (1 kg) (25 m²/s²) = 25 joules

Picture #2:
KE = (1/2) (mass) (speed²)
KE = (1/2) (2 kg) (10 m/s)²
KE = (1 kg) (100 m²/s²) = 100 joules

Picture #3:
GPE = (mass) x (gravity) x (height)
GPE = (20 kg) x (9.8 m/s²) x (2 m) = 392 joules

KE = (1/2) (mass) (speed²)
KE = (1/2) (20 kg) (5 m/s)²
KE = (10 kg) (25 m²/s²) = 250 joules

Picture #4:
GPE = (mass) x (gravity) x (height)
98 joules = (1 kg) x (9.8 m/s²) x (height)
Height = (98 joules) / (1 kg x 9.8 m/s²)
Height = 10 meters

Picture #5:
GPE = (mass) x (gravity) x (height)
39,200 Joules = (mass) x (9.8 m/s²) x (20 m)
Mass = (39,200 joules) / (9.8 m/s² x 20 m)
Mass = 200 kg

5 0

3 years ago

WhaT HAPPENS WHEN a net force act's <br> on a moving object

Mumz [18]

Answer: the object will have an acceleration and the object's velocity will change.
Explanation: I just know

4 0

3 years ago

In an Atwood machine the two masses (m1 =5.0kg and m2 = 3.0 kg) are released from rest, with m1 at a height of h=0.75 m above th

masya89 [10]

Answer:

Explanation:

m₁ is heavy so it will go down and m₂ will go up. Let common acceleration be a .

For downward acceleration of m₁

m₁g - T₁ = m₁a

For upward acceleration of m₂

T₂- m₂g = m₂a

adding

m₁g - T₁ +T₂- m₂g = (m₁+m₂)a

m₁g- m₂g +(T₂- T₁) = (m₁+m₂)a --------------- ( 1 )

For rotatory motion of disc of mass mp and moment of inertia I

(T₁ -T₂ )R = I α , α is angular acceleration ----------( 2 )

From 1 and 2

m₁g- m₂g - I α / R = (m₁+m₂)a

m₁g- m₂g - I a / R² = (m₁+m₂)a

m₁g- m₂g = (m₁+m₂)a + I a / R²

m₁g- m₂g = [(m₁+m₂) + mp k² / R² ] a ( k is radius of gyration of disk )

a = (m₁- m₂)g / [(m₁+m₂) +mp k² / R² ]

= (m₁- m₂)g / [(m₁+m₂) + .5 mp ] ( for cylinder k² / R² = .5 )

If h be the height by which m₁ falls and its velocity becomes v

v² = 2 a h

a = v² / 2h

v² / 2h = (m₁- m₂)g / [(m₁+m₂) + .5 mp ]

v²[(m₁+m₂) + .5 mp ] = 2(m₁- m₂) gh

- v²[(m₁+m₂) +2(m₁- m₂) gh = .5 mp v²

- v²[(m₁+m₂) +2(m₁- m₂) gh / .5 v ² = mp .

- 1.8² ( 5 + 3 ) + 2 ( 5 - 3 ) 9.8 x .75 / .5 x 1.8² = mp

- 25.92 + 29.4 / 1.62 = mp

2.15 kg = mp .

K.E of masses = 1/2 x 5 x 1.8² + 1/2 x 3 x 1.8²

= 12.96 J

Rotational KE of disc

= 1/2 I ω²

= 1/4 mp r²ω²

= 1/4 x mp x v²

= .25 x 2.15 x 1.8²

= 1.74 J

in percent terms

(1.74 / 12.96) x 100

= 13.5 %

5 0

3 years ago