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2 years ago

Please help me and thank you

Physics

1 answer:

fredd [130]2 years ago

8 0

Answer:

536.56 m/s

Explanation:

We'll begin by calculating the momentum of the Porsche. This can be obtained as follow:

Mass (m) of Porsche = 1361 kg

Velocity (v) of Porsche = 26.82 m/s

Momentum of Porsche =?

Momentum = mass × velocity

Momentum = 1361 × 26.82

Momentum of Porsche = 36502.02 Kgm/s

Finally, we shall determine the velocity you need to be running with in order to have the same momentum as the Porsche. This can be obtained as follow:

Your Mass = 68.03 kg

Your Momentum = Momentum of Porsche = 36502.02 Kgm/s

Your velocity =?

Momentum = mass × velocity

36502.02 = 68.03 × velocity

Divide both side by 68.03

Velocity = 36502.02 / 68.03

Velocity = 536.56 m/s

Thus you must be running with a speed of 536.56 m/s in order to have the same momentum as Porsche.

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If the small piston has an area of .004 square

denpristay [2]

The magnitude of the pressure : P = 56,250 N/m

<h3>Further explanation</h3>

Given

Area of 0.004 m²

Force 225 N

Required

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Solution

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3 years ago

A mustang, has an average velocity of 33 m/s while covering a course that is 21 miles long. (1 mile = 1609 m). How long did it t

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Answer:

t = 1023.9 seconds

Explanation:

Given that,

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So, it will take 1023.9 seconds to complete the course.

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2 years ago

A 30 kg child rides a 20 kg bicycle. Together, the child and the bicycle have a momentum of 110 kg-m/s. What is the velocity of

love history [14]

Answer:

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Explanation:

We have,

Mass of child is 30 kg and the mass of bicycle is 20 kg. The combined momentum of the child and the bicycle is 110 kg-m/s.

It is required to find the velocity of the boy and the bicycle. The momentum of an object is given in terms of mass and its velocity. So,

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$v=\dfrac{p}{M}\\\\v=\dfrac{110}{30+20}\\\\v=2.2\ m/s$

So, the velocity of the boy and the bicycle is 2.2 m/s.

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3 years ago

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<u>Rated </u>

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<h3>What is "current rating"?</h3>

The greatest current that a fuse is rated to carry for an infinite duration without significantly degrading the fuse element is known as the current rating.
There is also a large selection of power switching transistors that have voltage ratings well over 1000V and current ratings up to several hundred amps.

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When an electrical device receives its rated voltage and outputs its rated power, it flows at its rated current.
So, when a device is designed for a certain amperage, that amperage is referred to as the equipment's rated current.

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An electrical appliance's rating reveals the voltage range at which it is intended to operate as well as the current consumption at that range.
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1 year ago

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lutik1710 [3]

Answer:

1. Yes, it can occur adiabatically.

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$U_{2}-U_{1}=W$

This balance tell us that the internal energy changes may occur due to work that, in this case, si done over the system.

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$du=C_{v}dT$

Assuming $C_{v}$ constant,

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3 years ago