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4 years ago

Acids turned ___bases turned _and neutral stayed__

1 answer:

8 0

I'm not sure tbh, but if it helps, heres a game that helped me understand bases acids and neutrals for chem in 8th grade! http://static.lawrencehallofscience.org/scienceview/scienceview.berkeley.edu/html/showcase/flash/jui... I know it looks cheesy, but it helps! Chem is something youll have until college, and it helps to learn about it. You can make drinks using acids, bases, and neutrals!

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What are two ways to increase impulse?

Pepsi [2]

Answer:

increase the time the force acts or you could increase the number of temptations.

hope this helped!

5 0

4 years ago

A 15 kg cart is pushed on a frictionless surface from rest horizontally by a 30 N force. What is the cart's acceleration?

Rainbow [258]

Answer:

a. The cart's acceleration is 2 m/s^2

b. The cart will travel 100 m

c. The speed is 20 m/s

Explanation:

a. The acceleration of the cart can be calculated using Newton's second law:

F = m.a

Solving for a:

$\displaystyle a=\frac{F}{m}$

The cart has a mass of m=15 Kg and is applied a net force of F=30 N, thus:

$\displaystyle a=\frac{30}{15}$

$a=2\ m/s^2$

Now we use kinematics to find the distance and speed:

$\displaystyle x = v_o.t+\frac{at^2}{2}$

The cart starts from rest (vo=0). The distance traveled in t=10 seconds is:

$\displaystyle x = 0*10+\frac{2*10^2}{2}$

$x = 100\ m$

The cart will travel 100 m

The final speed is calculated by:

$v_f=0+2*10=20\ m/s$

The speed is 20 m/s

5 0

3 years ago

When two point charges are a distance dd part, the electric force that each one feels from the other has magnitude F.F . In orde

Harman [31]

Answer:

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. r' = r/2.

Explanation :

The electric force between two point charges is directly proportional to the product of charges and inversely proportional to the square of the distance between charges. It is given by :

$F=\dfrac{kq_1q_2}{r^2}$

r is the separation between charges

$F\propto \dfrac{1}{r^2}$

$r=\sqrt{\dfrac{1}{F}}$

If F'= 2F

$r'=\dfrac{1}{\sqrt{2F} }$

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. $r'=\dfrac{1}{\sqrt{2F} }$ . Hence, this is the required solution.

6 0

3 years ago

Why are renewable energy resources going to be important in our future

marshall27 [118]

Renewable resources are going to be important in our future because if we use up all of our NON-renewable resources now, then we’ll still have the renewable resources to depend on.
I hope this helped! :-)

3 0

4 years ago

8) 8 resistor is connected in **parallel** with a 6 resistor. This

lyudmila [28]

Answer:

The equivalent resistance of the combination is 3.42 ohms.

Explanation:

We have,

8 ohms resistor is connected in parallel with a 6 ohms resistor. It is required to find the equivalent resistance of this combination.

For a parallel combination, the equivalent resistance is given by :

$\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

Plugging the values of R₁ and R₂, we get :

$\dfrac{1}{R_{eq}}=\dfrac{1}{8}+\dfrac{1}{6}\\\\R_{eq}=3.42\ \Omega$

So, the equivalent resistance of the combination is 3.42 ohms.

4 0

4 years ago

Acids turned _______bases turned _________and neutral stayed______

Acids turned ___bases turned _and neutral stayed__