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Vinvika [58]
3 years ago
9

You are on a sled at the top of a hemispherical, snowy hill of radius 13 m. You begin to slide down the hill. How fast are you m

oving in m/s when you have made it 14 degrees down the hemisphere as seen below?

Physics
2 answers:
charle [14.2K]3 years ago
7 0

Answer:

13.90 m/s

Explanation:

from the diagram in the attachment

we can find height h

 h=rsin14=13sin14\\=3.15 m

now by energy conservation at two points we can write

velocity at 14 degrees down the hemisphere

v=\sqrt{2g(13-3.14)} =\sqrt{2\times9.81\times9.86} \\=13.90\text{ m/s}

8_murik_8 [283]3 years ago
4 0

Answer:

Explanation:

There will be loss of potential energy due to loss of height and gain of kinetic energy .

loss of height = R - R cos 14 ,    R is radius of hemisphere .

R ( 1 - cos 12 )

= 13 ( 1 - .978 )

h = .286 m

loss of potential energy

= mgh

= m x 9.8 x .286

= 2.8 m

gain of kinetic energy

1/2 m v ² = mgh

v² = 2 g h

v²  = 2 x 9.8 x 2.8

v = 7.40 m /s

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Answer:

Straining method

Explanation:

Straining method is the method that can be used to separate parts of a liquid mixture when the entire mixture can pass through a filter.

3 0
3 years ago
R: Law of Conservation of Energy Pre-Write
Bad White [126]

Answer:

V at C is 3.6 m/s

Explanation:

At A kinetic energy is zero and potential energy=mgh=0.5*9.81*0.6=2.943 J

By conservation of energy.

KE+PE=Constant

At C PE=0.6 J

the KE=2.943-0.6=2.343 J

KE=0.5*m*v^2

v=√[KE/(0.5*m)]=3.06 m/s

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3 years ago
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3 0
3 years ago
Read 2 more answers
N 1800kg car has an<br> of 3.8m/s? What is it<br> on the car?<br> acceleration<br> force acting
nevsk [136]

Answer:

6840 N

Explanation:

The force acting on the car can be found by using Newton's second law:

F = ma

where

F is the net force on the car

m is the mass of the car

a is its acceleration

For the car in this problem,

m = 1800 kg

a=3.8 m/s^2

Substituting,

F=(1800)(3.8)=6840 N

7 0
3 years ago
A 4.30 g bullet moving at 943 m/s strikes a 730 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
Ymorist [56]

Answer:

(a)2.7 m/s

(b) 5.52 m/s

Explanation:

The total of the system would be conserved as no external force is acting on it.

Initial momentum = final momentum

⇒(4.30 g × 943 m/s) + (730 g × 0) = (4.30 g × 484 m/s) + (730 g × v)

⇒ 730 ×v = (4054.9 - 2081.2) =1973.7

⇒v=2.7 m/s

Thus, the resulting speed of the block is 2.7 m/s.

(b) since, the momentum is conserved, the speed of the bullet-block center of mass would be constant.

V_{COM} = \frac{m_b}{m_b+m_{bl}}v_{bi}=\frac{4.30}{4.30+730}\times 943 m/s = 5.52 m/s

Thus, the speed of the bullet-block center of mass is 5.52 m/s.

4 0
4 years ago
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