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Vinvika [58]
3 years ago
9

You are on a sled at the top of a hemispherical, snowy hill of radius 13 m. You begin to slide down the hill. How fast are you m

oving in m/s when you have made it 14 degrees down the hemisphere as seen below?

Physics
2 answers:
charle [14.2K]3 years ago
7 0

Answer:

13.90 m/s

Explanation:

from the diagram in the attachment

we can find height h

 h=rsin14=13sin14\\=3.15 m

now by energy conservation at two points we can write

velocity at 14 degrees down the hemisphere

v=\sqrt{2g(13-3.14)} =\sqrt{2\times9.81\times9.86} \\=13.90\text{ m/s}

8_murik_8 [283]3 years ago
4 0

Answer:

Explanation:

There will be loss of potential energy due to loss of height and gain of kinetic energy .

loss of height = R - R cos 14 ,    R is radius of hemisphere .

R ( 1 - cos 12 )

= 13 ( 1 - .978 )

h = .286 m

loss of potential energy

= mgh

= m x 9.8 x .286

= 2.8 m

gain of kinetic energy

1/2 m v ² = mgh

v² = 2 g h

v²  = 2 x 9.8 x 2.8

v = 7.40 m /s

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Answer:

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tino4ka555 [31]

Answer:

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Explanation:

Solution:

At 300K:

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