Answer:
115 kPa
Explanation:
Use Bernoulli equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
Assuming no elevation change, h₁ = h₂.
P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²
Plugging in values:
(582,000 Pa) + ½ (1000 kg/m³) (1.28 m/s)² = P + ½ (1000 kg/m³) (30.6 m/s)²
P = 115,000 Pa
P = 115 kPa
Answer:
Explanation:
1760 yd/mi / 120 yd/field = 14⅔ fields/mi
You divide sort of the similar but vector is distance and displacement and scalar is just distance
In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.
<h3>What is freezing?</h3>
It is a physical change in which liquids give off heat to form solids.
We have 210.0 g of water at 0°C. We can calculate the amount of heat given off when it freezes into ice using the following expression.
Q = ΔH°fus × m
Q = 0.334 kJ/g × 210.0 g = 70.1 kJ
where,
- Q is the heat released.
- ΔH°fus is the latent heat of fusion.
- m is the mass.
In the freezing physical change, when 210.0 g of water a 0 degrees freezes into ice, it gives off 71.0 kJ of heat.
Learn more about freezing here: brainly.com/question/40140
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