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IceJOKER [234]
3 years ago
14

Mechanical locks can accept a variety of inputs as keys, including magnetic strips on ID cards, radio signals from name badges,

personal identification numbers (PINs) typed into a keypad, or some combination of these to activate an electrically powered servo to unlock the mechanism. _________________________
A) True
B) False
Physics
1 answer:
lidiya [134]3 years ago
3 0

Answer:

The answer is B) False

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A vector has a magnitude of 46.0 m and points in a direction 20.0° below the positive x-axis. A second vector, , has a magnitude
irina1246 [14]

Answer with Step-by -step explanation:

We are given that

b.\mid A\mid=46 m

\theta=20^{\circ} below the positive x-axis

Therefore, the angle made by vector A in counter clockwise direction when measure from positive x-axis=x=360-20=340^{\circ}

x-component of vector A=A_x=\mid A\mid cosx=46cos 340=46\times 0.94=43.24

y-Component of vector A=A_y=\mid A\mid sinx=46sin340=46(-0.34)=-15.64

Magnitude of vector B=86 m

The vector B makes angle with positive x- axis=x'=42^{\circ}

x-component of vector B=B_x=86cos42=63.64

y-Component of vector B=B_y=86sin42=57.62

Vector A=A_xi+A_yj=43.24i-15.64j

Vector B=B_xi+B_yj=63.64i+57.62j

Vector C=A+B

Substitute the values

C=43.24i-15.64j+63.64i+57.62j

C=106.88i+41.98j

c.Direction=\theta=tan^{-1}(\frac{y}{x})=tan^{-1}(\frac{41.98}{106.88})=21.5^{\circ}

The direction of the vector C=21.5 degree

6 0
3 years ago
A scientist carries out an experiment. How could she help other scientists judge the validity of her results?
NNADVOKAT [17]
One way to do it is she could right down the data that she got
4 0
3 years ago
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A locomotive has a mass of 200,000kg. It is moving at 4.5m/s. Find its momentum .
anastassius [24]
Momentum (p) = mass × velocity

P= 200,000×4.5

P= 900,000 .... answer !!
4 0
3 years ago
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What is solar power good for?
san4es73 [151]

Answer: the earth

Explanation: ask your teacher

3 0
2 years ago
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A test charge is placed at a distance of 2.5 × 10-2 meters from a charge of 6.4 × 10-5 coulombs. What is the electric field at t
Novosadov [1.4K]
Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance. 

E = kQ / d²

k = 9 x 10^9 N-m²/C²
Q = 6.4 x 10^-5 C
d = 2.5 x 10^-2 m

Substituting the given values to the equation, we have:
E = (9 x 10^9)(6.4 x 10^-5) / (2.5 x 10^-2) ²

Electric field at the test charge is 921600000 N/C
8 0
3 years ago
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