Answer:
a) 2.43 m/s
b) 4.83 m/s
c) 0.023 m/s²
Explanation:
a) Both cars cover a distance of 510 m in 210 s. Since car A has no acceleration
Speed = Distance / Time
![\text{Speed}=\frac{510}{210}=2.43\ m/s](https://tex.z-dn.net/?f=%5Ctext%7BSpeed%7D%3D%5Cfrac%7B510%7D%7B210%7D%3D2.43%5C%20m%2Fs)
Velocity of car A is 2.43 m/s
t = Time taken = 210 seconds
u = Initial velocity
v = Final velocity
s = Displacement = 510 m
a = Acceleration
c)
![s=ut+\frac{1}{2}at^2\\\Rightarrow 510=0\times 210+\frac{1}{2}\times a\times 210^2\\\Rightarrow a=\frac{510\times 2}{210^2}\\\Rightarrow a=0.023\ m/s^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20510%3D0%5Ctimes%20210%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%20210%5E2%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B510%5Ctimes%202%7D%7B210%5E2%7D%5C%5C%5CRightarrow%20a%3D0.023%5C%20m%2Fs%5E2)
Acceleration of car B is 0.023 m/s²
b)
![v=u+at\\\Rightarrow v=0+0.023\times 210\\\Rightarrow v=4.83\ m/s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20v%3D0%2B0.023%5Ctimes%20210%5C%5C%5CRightarrow%20v%3D4.83%5C%20m%2Fs)
Final velocity of car B is 4.83 m/s
A complex machine is a machine made up of two or more simple machines that make your work easier to do. There are six simple machines from which all complex machines are made. They include: The lever. The inclined plane
Hi there!
We can begin by calculating the time the ball takes to reach the highest point of its trajectory, which can be found using the following:
![t_{max} = \frac{vsin\theta}{g}](https://tex.z-dn.net/?f=t_%7Bmax%7D%20%3D%20%5Cfrac%7Bvsin%5Ctheta%7D%7Bg%7D)
Where:
tmax = (? sec)
vsinθ = vertical comp. of velocity = 10sin(48) = 7.43 m/s)
g = acceleration due to gravity (9.8 m/s²)
We can solve for this time:
![t_{max} = \frac{7.43}{9.8} = 0.758 s](https://tex.z-dn.net/?f=t_%7Bmax%7D%20%3D%20%5Cfrac%7B7.43%7D%7B9.8%7D%20%3D%200.758%20s)
When the ball is at the TOP of its trajectory, its VERTICAL velocity is equivalent to 0 m/s. Thus, we can consider this a free-fall situation.
We must begin by solving for the maximum height reached by the ball using the equation:
![d = y_0 + v_{0y}t + \frac{1}{2}at^2](https://tex.z-dn.net/?f=d%20%3D%20y_0%20%2B%20v_%7B0y%7Dt%20%2B%20%5Cfrac%7B1%7D%7B2%7Dat%5E2)
d = displacement (m)
vi = initial velocity (7.43 m/s)
a = acceleration due to gravity
d = displacement (m)
y0 = initial VERTICAL displacement (28m)
Plug in the values:
![d = 28 + 7.43(0.758) + \frac{1}{2}(-9.8)(0.758^2) = 30.817 m](https://tex.z-dn.net/?f=d%20%3D%2028%20%2B%207.43%280.758%29%20%2B%20%5Cfrac%7B1%7D%7B2%7D%28-9.8%29%280.758%5E2%29%20%3D%2030.817%20m)
Now, we can use the rearranged kinematic equation:
![t = \sqrt{\frac{2h}{g}}](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cfrac%7B2h%7D%7Bg%7D%7D)
![t = \sqrt{\frac{2(30.817)}{9.8}} = 2.51 s](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cfrac%7B2%2830.817%29%7D%7B9.8%7D%7D%20%3D%202.51%20s)
Add the two times together:
![0.758 + 2.51 = \boxed{3.266 s}](https://tex.z-dn.net/?f=0.758%20%2B%202.51%20%3D%20%5Cboxed%7B3.266%20s%7D)
Answer:
The answer is 5
Explanation:
The maximum interference is:
m * λ = d * sinθi
Where m = 0,1,2,3,...
The first minimum diffraction is:
λ = a * sinθd
|sinθi| < sinθd
Where
(|m| * λ)/d < λ/a
|m| < d/a = 2.5
|m|max = 2
It can be concluded that coherent monochromatic light passes through the slits, therefore the maximum number of interference is 5.